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masya89 [10]
3 years ago
9

Compare the number of moles calculated in parts a) 0.03 and b). 0.064. Which of the three possible reactions discussed is consis

tent with these results?
Chemistry
1 answer:
Snowcat [4.5K]3 years ago
6 0

Answer:don’t click link ur gonna get ur info taken

Explanation:

You might be interested in
an oxygen tank used for scuba diving has. avolume of 12.0 L .If the pressure of the tank is known to be 204.047 atm and the temp
Lapatulllka [165]

Answer: 101 moles of oxygen are contained in the tank

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 204.047  atm

V = Volume of gas = 12.0 L

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =22.0^0C=(22.0+273)K=295K

n=\frac{PV}{RT}

n=\frac{204.047atm\times 12.0L}{0.0821 L atm/K mol\times 295K}=101moles

Thus 101 moles of oxygen are contained in the tank

5 0
3 years ago
A piece of unknown metal weighs 348g. When the metal piece absorbs 6.64kj of heat , its temperature increases from 24.4C to 43.6
Morgarella [4.7K]

Answer:

This metal could be the aluminium with a specific heat of H = 993 \frac{J}{kgC}

Explanation:

A pie of unknown metal presents a mass (M) of 348 g. This metal is heated using energy (E) of 6.64 kJ and the temperature increases from T1 =24.4 to T2 =43.6°C. We can calculate the specific heat (H) of this metal as follows

H = \frac{E}{M*(T2-T1)}

We can replace previously presented data in this equation. After simplifying and converting to adequated units, we found that

H = \frac{6640 J}{0.348 Kg*(43.6-24.4) C} =\frac{6640 J}{6.686 KgC}

Finally, the specific heat of this metal is

H = 993 \frac{J}{kgC}

The aluminium could be the metal, its specific heat is similar to that found in this problem.

Finally,  we can conclude that this metal could be the aluminium with a specific heat of H = 993 \frac{J}{kgC}

7 0
3 years ago
Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M
liberstina [14]

Answer:

= \mathbf{C_3H_6O}

Explanation:

From the given information, since the molecular mass of the ion M+ is not given;

Let's assume M+ = 58.0423

So, by applying the 13th rule;

we will need to divide the mass by 13, after dividing it;

The quotient n = no. of carbon; &

The addition of the quotient (n) with the remainder r =  no. of hydrogen.

So;

\dfrac{58}{13}= 4 \ remainder \ 6

So;

C_nH_{n+r} = C_4H_{4+6}

= C_4H_{10}

From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing CH_4. Also, since the mass is an even number then Nitrogen is 0.

So, we have:

= \mathbf{C_3H_6O}

6 0
2 years ago
The fluid in a barometer (shown above) is mercury, Hg. Why point
PIT_PIT [208]

Answer:

Mercury responds to temperatures differently than water. When mercury is cold, the molecules bunch together, making it seem to be less liquid, and the opposite happens during heat.

Hope this helps!

5 0
3 years ago
The group in an experiment that is not exposed to the tested variable is called the group
kati45 [8]

Answer:

yes your answer is correct for this question.

5 0
3 years ago
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