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Inessa [10]
3 years ago
7

A speed-time graph is shown below:

Physics
1 answer:
topjm [15]3 years ago
6 0

Answer:

The answer to your question is 24 cm

Explanation:

The travel is divided into two sections:

1.- From 0 to 4 seconds

2.- From 4 to 8 seconds

In the first travel speed changes and on the second travel, speed is constant.

1.- Distance 1

   a = \frac{4 - 0}{4}

          a = 1 cm/s²

   d = \frac{v^{2}f - v^{2}o  }{2a}

   d = \frac{4^{2} - 0^{2} }{2(1)}

   d = \frac{16}{2}

          d = 8 cm

2.- Distance

    speed = \frac{distance}{time}

           distance = speed x time

           distance = (4) x 4

           distance = 16 cm

3.- Total distance

           d = 8 + 16

          <u> d = 24 cm</u>

         

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Please I need help........
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Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
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If forces acting on an object are unbalanced, which factor may result from an unbalanced force? A.The net force is negative. B.T
bezimeni [28]

Answer:

<h2>A. The net force is negative.</h2>

Explanation:

just took the test :)

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3 years ago
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Fill in the blanks for the following:
storchak [24]

Answer:

<em>a. 4.21 moles</em>

<em>b. 478.6 m/s</em>

<em>c. 1.5 times the root mean square velocity of the nitrogen gas outside the tank</em>

Explanation:

Volume of container = 100.0 L

Temperature = 293 K

pressure = 1 atm = 1.01325 bar

number of moles n = ?

using the gas equation PV = nRT

n = PV/RT

R = 0.08206 L-atm-mol^{-1}K^{-1}

Therefore,

n = (1.01325 x 100)/(0.08206 x 293)

n = 101.325/24.04 = <em>4.21 moles</em>

The equation for root mean square velocity is

Vrms = \sqrt{\frac{3RT}{M} }

R = 8.314 J/mol-K

where M is the molar mass of oxygen gas = 31.9 g/mol = 0.0319 kg/mol

Vrms = \sqrt{\frac{3*8.314*293}{0.0319} }= <em>478.6 m/s</em>

<em>For Nitrogen in thermal equilibrium with the oxygen, the root mean square velocity of the nitrogen will be proportional to the root mean square velocity of the oxygen by the relationship</em>

\frac{Voxy}{Vnit} = \sqrt{\frac{Mnit}{Moxy} }

where

Voxy = root mean square velocity of oxygen = 478.6 m/s

Vnit = root mean square velocity of nitrogen = ?

Moxy = Molar mass of oxygen = 31.9 g/mol

Mnit = Molar mass of nitrogen = 14.00 g/mol

\frac{478.6}{Vnit} = \sqrt{\frac{14.0}{31.9} }

\frac{478.6}{Vnit} = 0.66

Vnit = 0.66 x 478.6 = <em>315.876 m/s</em>

<em>the root mean square velocity of the oxygen gas is </em>

<em>478.6/315.876 = 1.5 times the root mean square velocity of the nitrogen gas outside the tank</em>

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Answer:no it is staying the same speed

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Over a period of operation, the useful work output of the fluorescent bulb was
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