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Margarita [4]
3 years ago
9

Over a period of operation, the useful work output of the fluorescent bulb was

Physics
1 answer:
Nadya [2.5K]3 years ago
5 0

Answer:

199.0521 Will be the answer

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A horizontal surface of area 0.321 m2has an electric flux of 123 N.m2/C passing through it at an angle of 25° to the horizontal.
ValentinkaMS [17]

Answer:

electric filed is 907 N/C

Explanation:

Given data

surface of area = 0.321 m²

electric flux of 123 N.m²/C

angle = 25°

to find out

magnitude of the electric field

solution

we know flux formula that is

flux = electric filed × area

put all value

123 = electric filed × 0.321 sin(25)

electric filed = 123 /  0.321 sin(25)

electric filed = 906.67

so electric filed is 907 N/C

7 0
3 years ago
Light striking a mirror at a 50° angle will be reflected at an angle _____.
Stells [14]
Equal to 50


law of reflection: angle of incidence equals angle of reflection
5 0
4 years ago
Read 2 more answers
The diagram is a real world example of the first and second laws of thermodynamics. It shows how thermal energy is used to gener
Dmitriy789 [7]

Answer:

First law: kinetic energy is used to turn an electric generator

Second law: some thermal energy is lost to the environment as it travels through the system

Explanation:

The first law of thermodynamics is known as the law of conservation of energy. It states that energy can neither be created nor destroyed but can only be transferred or changed from one form to another. When thermal energy is used to generate electricity, the kinetic energy of the steam is used to turn the electric generator (thereby producing electrical energy).

The second law of thermodynamics states that energy transfer or transformation leads to an increase in entropy resulting in the loss of energy. This law also states that as energy is transferred or transformed, some is lost in a form that is unusable. When thermal energy is used to generate electricity, some of the thermal energy is lost to the environment as it travels through the system.

7 0
3 years ago
Read 2 more answers
O prevent tank rupture during deep-space travel, an engineering team is studying the effect of temperature on gases confined to
Ira Lisetskai [31]

To calculate for the pressure of the system, we need an equation that would  relate the number of moles (n), pressure (P), and temperature (T) with volume (V). There are a number of equations that would relate these values however most are very complex equations. For simplification, we assume the gas is an ideal gas. So, we use PV = nRT.<span>

PV = nRT  where R is the universal gas constant
P = nRT / V</span>

<span>P = 3.40 mol ( 0.08205 L-atm / mol-K ) (251 + 273.15 K) / 1.75 L </span>

<span>P = 83.56 atm</span>

<span>
</span>

<span>Therefore, the pressure of the gas at the given conditions of volume and temperature would be 83.56.</span>

7 0
3 years ago
A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east​
elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: 56.31^o

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\

Now we can find the value of the angle by using the arctan function:

tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o

6 0
3 years ago
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