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Rasek [7]
3 years ago
6

How many water molecules are in a block of ice containing 1.50 mol of water (H2O)?

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
5 0
1.50 moles H20(6.02*10^23 molecules/1 mole)
9.03*10^23 molecules
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How does a buffer work
Liono4ka [1.6K]

A buffer is simply a mixture of a weak acid and its conjugate base or a weak base and its conjugate acid. Buffers work by reacting with any added acid or base to control the pH.

Hope this helps

8 0
3 years ago
What two forces act in the nucleus to create a 'nuclear tug-of-war'?
Alex787 [66]

Answer:

Electrostatic repulsion, strong nuclear force

Explanation:

The nucleus consists of protons and neutrons. protons are positively charged while neutrons possess no charge.

Since protons are positively charged, they repel each other strongly (like charges repel). This strong repulsion of like charges makes the nucleus somewhat unstable leading to spontaneous fission of heavy nuclei.

However, an opposing force called nuclear attractive force tends to hold the nucleons together. This attraction occurs when two nucleons are bonded by a particle called a π meson.

Hence, the two forces that act in the nucleus to create a  'nuclear tug-of-war' are electrostatic repulsion and a strong nuclear force.

5 0
3 years ago
5C + 6O2 = ? What will be the product of molecules formed from this equation?
harina [27]

Answer:5 moles ofCarbonmonoxide and 3.5 moles of oxygen gas.This in combine to yield carbon dioxide.

Explanation:

5C + 6O2----------5CO + 7/2O2.

When carbon combine with oxygen, carbon monoxide is formed first and it later recombine with oxygen to yield carbon dioxide.

6 0
4 years ago
Read 2 more answers
Let's say that you were given the following
mezya [45]

Answer:

V2~0.4839M

Explanation:

We're going to use Boyles law to answer the question.

Boyle's law:

P1V1=P2V2

P1=151mmHg

P2=166mmHg

V1=0.532L

V2=?

V2=(P1 x V1)/P2

V2=(151 x 0.532)/166

V2~0.4839M

Hope it helps:)

8 0
3 years ago
Since vinegar is 5% acetic acid and 95% water, find the mole ratio of acetic acid to water in 100 g of vinegar? Hint: Instead of
Oksanka [162]

The mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.

<h3>What is the mole ratio of acetic acid to water in 100 g of vinegar?</h3>

The mole ratio of acetic acid to water in 100 g of vinegar is determined from their percentage composition.

The percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water.

In 100 g of vinegar, there are 5 g of acetic acid and 5 g of water.

Moles = mass/molar mass

molar mass of acetic acid = 62 g/mol

molar mass of water = 18 g/mol

moles of vinegar = 5/62 = 0.08

moles of water = 95/18 = 5.28

total moles = 5.36

Mole ratio of vinegar to water = 0.08/5.36 : 5.28/5.36

Mole ratio of vinegar to water = 0.015 : 0.985

In conclusion, the mole ratio is determined from the percentage composition of acetic acid and water in vinegar.

Learn more about mole ratio at: brainly.com/question/19099163

#SPJ1

7 0
2 years ago
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