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2 years ago

Suppose Orville measures the length to be 1.55 cm. If the correct value is 1.32 cm, find Orville's % error.

Chemistry

1 answer:

Step2247 [10]2 years ago

8 0

Answer:

Error in measure= 1.55-1.32= 0.23

Orville's % error = 0.23/1.32*100% = 17.42%

Explanation:

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CHEMISTRY HELP PLEASE!

WINSTONCH [101]

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3 years ago

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How many moles of lithium nitrate<br> (LINO3) are in 256 mL of a 0.855 M<br> solution?

sweet [91]

Answer:

There are 0.219 mol of LINO3

7 0

3 years ago

What is the mass of 0.45 moles of Sodium?

ch4aika [34]

Answer:

10.35

Explanation:

multiply moles by molar mass from periodic table

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2 years ago

LICUICY NICULUM

Evgen [1.6K]

Answer:

Missing component

Cl₂

H₂O

Explanation:

Reaction given:

? + 2NaBr → 2NaCl+Br

Mg+? → MgO+H2

missing component = ?

Solution:

Reaction 1

? + 2NaBr -----→ 2NaCl + Br

if we look at the reactants and products there is one element is in product side but not shown in the reactant side.

In products there are following atoms

Na (Sodium)

Cl (Chlorine)

Br (Bromine)

In Reactant there are following atoms

Na (Sodium)

Br (Bromine)

So only Chlorine is missing in the reactant side.

if we put chlorine in the reactant then this reaction will be complete

Cl + 2 NaBr -----→ 2NaCl + Br

So chlorine react with water and give sodium chloride and bromine molecule, this is a single displacement reaction and chlorine replace bromine in the above reaction

Now balance the equation

Cl₂ + 2 NaBr -----→ 2NaCl + Br₂

So, the missing component is

Cl₂

____________

Reaction 2

Mg + ? ---------→ MgO + H₂

if we look at the reactants and products there are two element in product side but not shown in the reactant side.

In products there are following atoms

Mg (Magnesium)

O (Oxygen)

H (Hydrogen)

In Reactant there is only one following atom

Mg (Magnesium)

So Oxygen and Hydrogen is missing in the reactant side.

if we put water molecule (H₂O) in the reactant then this reaction will be complete

Mg + H₂O ---------→ MgO + H₂

in this reaction magnesium (Mg) react with water (H₂O) and give magnesium oxide and hydrogen gas.

So, the missing component is

H₂O

3 0

3 years ago

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If a student has 125 mL of a 4.00 M CuSO4 solution and needs a 1.50 M solution, what volume do they need to dilute it to?

lara31 [8.8K]

Answer:

333.3mL

Explanation:

Using the formula as follows:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question,

C1 = 4.00M

C2 = 1.50M

V1 = 125mL

V2 = ?

Using C1V1 = C2V2

4 × 125 = 1.5 × V2

500 = 1.5V2

V2 = 500/1.5

V2 = 333.3mL

Therefore, the CuSO4 solution needs to be diluted to 333.3mL to make 1.50 M solution.

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2 years ago