I think c is used in electric power plants.
Answer:
i know it is alot but that is how are teacher told us to do, hope this is correct
Explanation:
a. 2.6
b. 12.0
Explanation:
a.
First, we will calculate the molar concentration of HCl.
M = mass of HCl / molar mass of HCl × liters of solution
M = 0.40 g / 36.46 g/mol × 4.5 L
M = 2.4 × 10⁻³ M
HCl is a strong monoprotic acid, so [H⁺] = 2.4 × 10⁻³ M. The pH is:
pH = -log [H⁺]
pH = -log 2.4 × 10⁻³ = 2.6
b.
First, we will calculate the molar concentration of NaOH.
M = mass of NaOH / molar mass of NaOH × liters of solution
M = 0.80 g / 40.00 g/mol × 2.0 L
M = 0.010 M
NaOH is a strong base with 1 OH⁻, so [OH⁻] = 0.010 M. The pOH is:
pOH = -log [OH⁻]
pOH = -log 0.010 = 2.0
The pH is:
14.00 = pH + pOH
pH = 14.00 - pOH = 14.00 - 2.0 = 12.0
Answer:
The positive charge in carbon is C
Explanation:
Atomic weight: An atom consists of protons, neutrons and electrons. Atomic mass is the sum of the number of protons and neutrons. The average weight of mass is called atomic mass of that atom.
The positive charge of an atom is proton.
The atomic weight of carbon = 12.0107 g/mol
Avogadro's number = 6.023×10⁻²³ atom/ mol
Charge = 1.602×10⁻¹⁹ C
The weight of carbon = 0.9 kg = 900 gram
Number of protons in carbon = 6
The positive charge in carbon is
=No. mole× Avogadro's Number× No. proton × charge per proton
C
Becouse melting point and cooling point are two opposite things one is 100degrees nd other 0degrees
There are 4 quantum numbers that can be used to describe the space of highest probability an electron resides in.
First quantum number is the principal quantum number- n , states the energy level.
Second quantum number states the angular momentum quantum number - l,
states the subshell and the shape of the orbital
values of l for n energy shells are from 0 to n-1
third is magnetic quantum number - m, which tells the specific orbital.
fourth is spin quantum number - s - gives the spin of the electron in the orbital
here we are asked to find l for 3p1
n = 3
and values of l are 0,1 and 2
for p orbitals , l = 1
therefore second orbital for 3p¹ is 1.