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Gemiola [76]
3 years ago
11

If a mixture of two metals was separated based on one metal's ability to be drawn into a thin wire, which property listed below

was important? ductility conductivity luster malleability
Chemistry
1 answer:
IrinaK [193]3 years ago
6 0

Ductility because ductility is the ability to be stretched and be made into wires.

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Which of the following is not true of alloys?
Scilla [17]
Option d: copper.

Because copper is an element, not a mixture.

7 0
3 years ago
Which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22°C and 100 kPa?
LenKa [72]

The volume could be calculated by using  <span>V = n RT / P </span>

In which V = Volume
n = number of Moles
R= The Gas constant
T = Temperature (ideally this would be in Kelvin, but i don't see it in the option)
P = Pressure


I believe the answer is

 <span>V = (1.5mol) (0.08205 L*kPa/K*mol) (22Celsius)/100 kPa 


</span>
6 0
3 years ago
What diffuses more quickly: tetracarbon decahydride (C4H10) or iodine (12)? By how much?
ValentinkaMS [17]

Answer: Butane will effuse more quickly because it has a smaller molar mass

Explanation:

Molar mass of C4H10 = 58.123 g/mole

Molar mass of I2 = 253.808 g/mole

5 0
3 years ago
In which of the following compounds does the carbonyl stretch in the IR spectrum occur at the lowest wavenumber?
klio [65]

Answer:

a. Cyclohexanone

Explanation:

The principle of IR technique is based on the <u>vibration of the bonds</u> by using the energy that is in this region of the electromagnetic spectrum. For each bond, there is <em>a specific energy that generates a specific vibration</em>. In this case, you want to study the vibration that is given in the carbonyl group C=O. Which is located around 1700 cm-1.

Now, we must remember that the <u>lower the wavenumber we will have less energy</u>. So, what we should look for in these molecules, is a carbonyl group in which less energy is needed to vibrate since we look for the molecule with a smaller wavenumber.

If we look at the structure of all the molecules we will find that in the last three we have <u>heteroatoms</u> (atoms different to carbon I hydrogen) on the right side of the carbonyl group. These atoms allow the production of <u>resonance structures</u> which makes the molecule more stable. If the molecule is more stable we will need more energy to make it vibrate and therefore greater wavenumbers.

The molecule that fulfills this condition is the <u>cyclohexanone.</u>

See figure 1

I hope it helps!

4 0
3 years ago
In the space provided, for each element, type the ionic charge of an atom with a full set of valence electrons. Then, type the n
kobusy [5.1K]

11. ionic charge +1, helium.

12. ionic charge 2-, neon.

13. ionic charge 3+, neon.

3 0
3 years ago
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