The momentum of the second ball was 15 kg.m/s.
<h3>What is inelastic collision?</h3>
In which collision some amount of kinetic energy of the system is lost that called inelastic collision. In purely inelastic collision, two bodies stick together. But principle of conservation of linear momentum is obeyed.
In the given question,
Two balls collide and after collision, the final momentum of the system = 18 kg.m/s.
Initial velocity of 1st ball of mass 3 kg is 1 m/s.
So, Initial momentum of first ball = mass × velocity = (3 kg) × (1 m/s) = 3 kg.m/s.
According to Principle of conservation of linear momentum for this inelastic collision,
Initial momentum of first ball + initial momentum of second ball = final momentum of the system
⇒ initial momentum of second ball = final momentum of the system - Initial momentum of first ball
= 18 kg.m/s - 3 kg.m/s.
= 15 kg.m/s.
Hence, initial momentum of second ball = 15 kg.m/s.
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ionic compound. The atom that lost the electron becomes a cation, and the atom that gains an electron becomes an anion. The cation and anion bond together because they have opposite charges to form an ionic compound. The question may be looking for just cation or anion, though.
Answer:
12.5 m/s
Explanation:
In a acceleration time graph the area under the curve gives the change in velocity of the object. Here object starts at rest and therefore initial velocity is 0. After 5 seconds acceleration is 5m/s2.
change in velocity=area under the curve
change in velocity= 0.5*acceleration* change in time
v-0=0.5*5*5
v=12.5 m/s
Answer:
(C) 16 radians
Explanation:
The angular displacement is given by the following equation:
Here
Is the angular displacement of the body at the indicated time (t).
Is the angular velocity of the body at the initial moment.
Is the angular acceleration of the body.
The disk starts from rest, so 
Replacing the given values:
Answer:
x = 0.9 m
Explanation:
For this exercise we must use the rotational equilibrium relation, we will assume that the counterclockwise rotations are positive
∑ τ = 0
60 1.5 - 78 1.5 + 30 x = 0
where x is measured from the left side of the fulcrum
90 - 117 + 30 x = 0
x = 27/30
x = 0.9 m
In summary the center of mass is on the side of the lightest weight x = 0.9 m
