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2 years ago

How is electronegativity related to the position of elements on the periodic table and covalent bonding?

Physics

1 answer:

andrezito [222]2 years ago

6 0

Electrons in a polar covalent bond are shifted toward the more electronegative atom

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A mercury in barometer shows a height of 70cm.What height would be shown in the barometer at the same place if water density 1.0

Pie

Answer:

P = d g h pressure due to density of liquid of height h

d1 g h1 = d2 g h2 since P1 equals P2

d1 h1 = d2 h2 and the density of Hg is 13.6 times that of water

h2 = (d1 / d2) * h1 = 13.6 * 70 cm = 952 cm or 9.52 m

8 0

2 years ago

What is the smallest possible number of products in a decomposition reaction?

Vaselesa [24]

The smallest number of products in a decomposition reaction is two because there is 1 reactant that breaks down and when it does break down there must be two products. It is generally more, though.

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2 years ago

What is the frequency of a radio wave with an energy of 3.686 × 10−24 j/photon?answer in units of hz?

Makovka662 [10]

To solve this problem, we have to use the formula:

E = h f

where E is total energy, h is Plancks constant 6.626x10^-34 J s, f is frequency

f = E / h

f = 3.686 × 10−24 J / (6.626x10^-34 J s)

4 0

2 years ago

An air balloon is moving upward at a constant speed of 3 m/s. Suddenly a passenger realizes that she left her camera on the grou

frosja888 [35]

Answer:t=0.3253 s

Explanation:

Given

speed of balloon is $u=3\ m/s$

speed of camera $u_1=20\ m/s$

Initial separation between camera and balloon is $d_o=5\ m$

Suppose after t sec of throw camera reach balloon then,

distance travel by balloon is

$s=ut$

$s=3\times t$

and distance travel by camera to reach balloon is

$s_1=ut+\frac{1}{2}at^2$

$s_1=20\times t-\frac{1}{2}gt^2$

Now

$\Rightarrow s_1=5+s$

$\Rightarrow 20\times t-\frac{1}{2}gt^2 =5+3t$

$\Rightarrow 5t^2-17t+5=0$

$\Rightarrow t=\dfrac{17\pm \sqrt{17^2-4(5)(5)}}{2\times 5}$

$\Rightarrow t=\dfrac{17\pm 13.747}{10}$

$\Rightarrow t=0.3253\ s\ \text{and}\ t=3.07\ s$

There are two times when camera reaches the same level as balloon and the smaller time is associated with with the first one .

(b)When passenger catches the camera time is $t=0.3253\ s$

velocity is given by

$v=u+at$

$v=20-10\times 0.3253$

$v=16.747\ m/s$

and position of camera is same as of balloon so

Position is $=5+3\times 0.3253$

$=5.975\approx 6\ m$

8 0

2 years ago

What’s the correct answer

White raven [17]

Looks like you simply substitute the length of the femur

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2 years ago