Answer:
1-(tert-butoxy)-2-methylpropane
Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.
Explanation:
<em>Structural formula is attached</em>
IUPAC naming rules
1. start numbering the chain from the functional group. In this compound we start from oxygen side.
2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.
3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.
4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane
5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane
The correct answer is C : energy level.
As you can see in the image of the periodic table presented below, periods are the horizontal columns of the periodic table.
Elements belonging to the same period have the same electron shell, the same number of orbits filled with electrons.
Elements of the same period have similar chemical and physical characteristics
Answer:
The method of hurrying up a reaction by decreasing its activation energy is called as catalysis, and the circumstance that's added to reduce the activation energy is termed as the catalyst.
Explanation:
Organic catalysts are named as enzymes. Enzymes are protein particles in cells which act as catalysts. Enzymes are proteid particles in groups which act as catalysts. Enzymes rush up biochemical effects in the thing but do not become used up in the method. Nearly all biochemical effects in living things require enzymes. Among an enzyme, biochemical effects go extremely quicker than they would without the enzyme.
<span>Now consider a low pressure area on a disk as shown below.A parcel of air at point A would move toward the center of the low pressure area. That movement would take it farther away from the center of the disk and therefore it would move to the west. A parcel of air at B would move toward the center of the low pressure area which would also take it closer to the center of the spinning disk where its speed is greater than the surrounding points. It would appear to move to the east. With A moving to the west and B moving to the east the line from A to B is rotating counterclockwise.</span>
