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zloy xaker [14]
3 years ago
13

Write the equation of the parabola that has the vertex at point (−0.5, 2.3) and passes through the point (5, 2.75).

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

The vertex form of equation of a parabola:

y=a(x-h)^2+k

(h, k) - vertex

We have the vertex (-0.5, 2.3). Therefore h = -0.5 and k = 2.3.

Substitute:

y=a(x-(-0.5))^2+2.3\\\\y=a(x+0.5)^2+2.3

We have the point (5, 2.75). Put the coordinstes of the point to the equation of parabola:

2.75=a(5+0.5)^2+2.3\qquad\text{subtract 2.3 from both sides}\\\\0.45=a(5.5)^2\\\\0.45=30.25a\qquad\text{divide both sides by 30.25}\\\\a=\dfrac{0.45}{30.25}\\\\a=\dfrac{45:5}{3025:5}\\\\a=\dfrac{9}{605}

Answer:\ \boxed{y=\dfrac{9}{605}(x+0.5)^2+2.3}


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Answer:

There are 47.12 liters in 12.4 gallons of gasoline.

Option C is correct option.

Step-by-step explanation:

Total Gasoline bought = 12.4 gallons

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1 gallons = 3.8 liters

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What is the solution(s) to the system of equations y = x² +4 and y = 2x + 4
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Answer:

(x,y) = (0,4)~ \text{and}~ (x,y) = (2,8)

Step by step explanation:

y = x^2 +4~~~~~~~~~...(i)\\\\y = 2x +4~~~~~~~~~...(ii)\\\\\text{From (i) and (ii):}\\\\~~~~~~x^2 +4 = 2x+4\\\\\implies x^2 = 2x\\\\\implies x^2 -2x = 0\\\\\implies x(x-2) = 0\\\\\implies x =0,~ x = 2

\text{Substitute x = 0 in eq (i):}\\\\y = 0^2 +4 = 4\\\\\text{Substitute x = 2 in eq (i):}\\\\y=2^2+4 = 4+4 = 8\\\\\text{Hence,}~ (x,y)= \{(2,8), (0,4)\}

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