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An astronaut holds a rock 100m above the surface of Planet X. The rock is then thrown upward with a speed of 15m/s, as shown in

Harlamova29_29 [7]

The acceleration due to gravity of the planet X is 1 m/s².

The given parameters;

height above the ground, h = 100 m
initial velocity of the rock, u = 15 m/s
time of motion of the rock, t = 10 s

The acceleration due to gravity is calculated as follows;

$h = ut - \frac{1}{2} gt^2\\\\100 = 15(10) - (0.5\times 10^2)g\\\\100 = 150 - 50g\\\\50g = 150-100\\\\50g = 50\\\\g = 1 \ m/s^2$

Thus, the acceleration due to gravity of the planet X is 1 m/s²

Learn more here: brainly.com/question/24564606

7 0

2 years ago

The motion that is not repeated in regular interval of time is called....? <br>please help me!

Misha Larkins [42]

Answer:

<h3>Motion which repeats itself after regular intervals of time is known as periodic motion.</h3>

8 0

3 years ago

Read 2 more answers

A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu

Setler79 [48]

<h2>Given :</h2>

total charge = 9.0 mC = 0.009 C

Each electron has a charge of :

$1.6 \times 10 {}^{ - 19} \: C$

For producing 1 Cuolomb charge we need :

$\mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }$

$\dfrac{10 {}^{19} }{1.6}$

$\dfrac{10\times 10 {}^{19} }{16}$

$\dfrac{100 \times 10 {}^{18} }{16}$

$\mathrm{6.24 \times 10 {}^{18} \: \: electrons}$

Now, for producing 0.009 C of charge, the number of electrons required is :

$0.009 \times 6.24 \times {10}^{18}$

$0.05616 \times 10 {}^{18}$

$\mathrm{5.616 \times 10 {}^{16} \: \: electons}$

_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

$\mathrm{5.616 \times 10 {}^{16} \: \: electrons}$

Number of electrons passing through it in 1 Second is :

$\dfrac{5.616 \times {10}^{16} }{3.6}$

$\mathrm{1.56 \times 10 {}^{16} \: \: electrons}$

Now, in 10 seconds the number of electrons passing through it is :

$10 \times \mathrm{1.56 \times 10 {}^{16} \: \: }$

$\mathrm{1.56 \times 10 {}^{17} \: \: electrons}$

_____________________________

$\mathrm{ \#TeeNForeveR}$

6 0

2 years ago

What is the force on a 1,000 kilogram-elevator that is falling freely under the acceleration of gravity only?

likoan [24]

   Force = (mass) · (acceleration)

   = (1,000 kg) · (9.8 m/s²)

   = 9,800 newtons

Why are you still having a problem with F = M · a ?

8 0

3 years ago

A 100.0 gram sample of Polonium-210 is contained for 552 days. How many half-lives occur during this period of time, if the half

Leto [7]

Answer:

4 half-lives will occur during this period of time.

Explanation:

Formula used :

$a_o=a\times e^{-\lambda t}$

$\lambda =\frac{0.693}{t_{1/2}}$

$a=\frac{a_o}{2^n}$

where,

a = amount of reactant left after n-half lives and time t

$a_o$ = Initial amount of the reactant.

$\lambda =$ decay constant

$t_{1\2}$ = half life of an isotope

n = number of half lives

We have :

$a_o=100.0 g$

a = ?

t = 552 days

$t_{1/2}=138 days$

$a=100.0 g\times e^{-\frac{0.693}{138}\times 552}$

$a=6.254 g$

$6.254 g=\frac{100.0 g}{2^n}$

$2^n=\frac{100.0 g}{6.254 g}$

n = 4

4 half-lives will occur during this period of time.

4 0

3 years ago