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Fed [463]
3 years ago
7

In a phospholipid, which components constitute the hydrophilic head? Select the correct answer below: Question 1 options: amino-

alcohol modified phosphate, ester groups, and glycerol fatty acid and glycerol phosphate and fatty acid only the amino alcohol that modifies the phosphate group
Chemistry
1 answer:
KIM [24]3 years ago
4 0

Answer: Option (a) is the correct answer.

Explanation:

A lipid that contains a phosphate group in its molecule is known as a phospholipid.

These are the primary molecules present in a plasma membrane. These tend to contain two hydrophobic fatty acid tails and one hydrophilic head.

Hydrophilic means water loving in nature.

As phosphate group is a polar group due to this the hydrophilic region present in a phospholipid is able to interact with water.

In an amino-alcohol modified phosphate, ester groups, and glycerol, the glycerol is hydrophobic in nature. It also contains two fatty acids and a phosphoric acid which are present as ester. The polar head that mainly consists of phosphate group is hydrophilic and thus, it helps in combining to a water molecules.

Hence, we can conclude that in a phospholipid, amino-alcohol modified phosphate, ester groups, and glycerol are the components which constitute the hydrophilic head.

 

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Answer:

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Explanation:

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4 years ago
Which feature of a balanced chemical equation demonstrates the law of conservation of mass?
stealth61 [152]

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2 years ago
Describe in detail how to prepare 500.0 mL of a 2.5 M calcium chloride solution. Calcium chloride is purchased as a solid. TO pi
antoniya [11.8K]

Answer:

In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the solute gets completely soluble add more water up till the mark of 500 ml.

Explanation:

Concentration of calcium chloride = 2.5 M

Volume of the solution = 500.0 ml = 0.5000 L

Moles of calcium chloride = n

c=\frac{n}{V(L)}

n = moles of solute

c = concentration of solution

V = volume of the solution in L

2.5 M=\frac{n}{0.5000 L}

n=2.5 M\times 0.5000 L = 1.2500 mol

n=\frac{\text{Mass of calcium chloride}}{\text{Molar mass of calcium chloride}}

1.2500 mol=\frac{\text{Mass of calcium chloride}}{111 g/mol}

Mass of calcium chloride = 111 g/mol × 1.2500 mol = 138.75 g

In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the the solute gets completely soluble add more water up till the mark of 500 ml.

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if a fast moving cold air mass overtakes a slow-moving warm air mass in July, what type of weather would you predict to occur?
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