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Scilla [17]
4 years ago
6

Consider 80.0-g samples of two different compounds consisting of only carbon and oxygen. One of the compounds consists of 21.8 g

of carbon, and the other has 34.3 g of carbon. Determine the ratio in whole numbers of the masses of carbon that combine with 1.00 g of oxygen between the two compounds.
Chemistry
1 answer:
goldenfox [79]4 years ago
6 0

Answer:

  • <u><em>Ratio of the  mass carbon that combines with 1.00 g of oxygen in compound 2 to the mass of carbon that combines with 1.00 g of oxygen in compound 1 = 2</em></u>

Explanation:

First, detemine the mass of oxygen in the two samples by difference:

  • mass of oxygen = mass of sample - mass of carbon

Item                     Compound 1                        Compound 2

Sample                80.0 g                                    80.0 g

Carbon                 21.8 g                                    34.3 g

Oxygen:               80.0 g - 21.8g = 58.2 g         80.0 g - 34.3 g = 45.7 g

Second, determine the ratios of the masses of carbon that combine with 1.00 g of oxygen:

  • For each sample, divide the mass of carbon by the mass of oxygen determined above:

Sample              Mass of carbon that combines with 1.00 g of oxygen            

Compound 1      21.8 g / 58.2 g =  0.375

Compound 2     34.3 g / 45.7 g = 0.751

Third, determine the ratio of the masses of carbon between the two compounds.

  • Divide the greater number by the smaller number:

  • Ratio = 0.751 / 0.375 = 2.00 which in whole numbers is 2
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Answer:

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Explanation:

The titration is:

CuCl₂(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + 2 NaCl(aq)

In solution, before the reaction, the ions are Cu²⁺ and Cl⁻. The addition of NaOH (Na⁺ + OH⁻) produce the precipitation of Cu²⁺ forming Cu(OH)₂(s). When you reach the equivalence point, there is no Cu²⁺ because precipitates completely. All OH⁻ ions reacts when are added but when Cu²⁺ is finished, excess OH⁻ ions still in solution helping to detect the equivalence point.

Thus, ions present after the equivalence point are:<em> Cl⁻, Na⁺</em> (Don't react, spectator ions), and <em>OH⁻</em>.

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3 years ago
Question 8 of 8&gt; 0 Attempt 2 A chemist needs to determine the concentration of a sulfuric acid solution by titration with a s
Nesterboy [21]

Answer:

12.29 M

Explanation:

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5 0
3 years ago
A mixture of methanol and methyl acetate contains 15.0 wt% methanol.
Usimov [2.4K]

The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h

5 0
3 years ago
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blsea [12.9K]
To find the empirical formula you would first need to find the moles of each element:

58.8g/ 12.0g = 4.9 mol C

9.9g/ 1.0g = 9.9 mol H

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Then you divide by the smallest number of moles of each:

4.9/1.96 = 2.5

9.9/1.96 = 6

1.96/1.96 = 1

Since there is 2.5, you find the least number that makes each moles a whole number which is 2.

So the empirical formula is C5H12O2.
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Daniel [21]

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The alloy of iron-nickel can be abbreviated as FeNi, which implies iron-nickel.

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Thus, FeNi or NiFe is an acronym used to refer a family of iron alloys.

Learn more about iron alloys here: brainly.com/question/24842164

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