Answer: 2.04L
Explanation:
coldest temperature = -10°C
mass of solvent = 6.50kg
freezing point depression = kb*m
Where kb = molar freezing point depression constant, 1.86
10 = 1.86 * molality of ethylene glycol
10 = 1.86 * moles of ethylene glycol/mass of solvent
10 = 1.86 * moles of ethylene glycol/6.5
10*6.5 = 1.86 * moles of ethylene glycol
Moles of ethylene glycol = 65/1.86
Moles of ethylene glycol = 36.11
36.11 mol * 62.1 g/mol = 2242.43g = 2.24kg
1 L = 1000 mL x 1.11 g/mL = 1100 g = 1.1 kg
2.24 kg / 1.10 kg/L = 2.04 L
B; Seismometer would be the answer.
The subscript for H in the empirical formula for this compound is 3.
There are 3 steps involved in the construction of empirical formula.
Calculation of empirical formula is as under as ...
Step 1: Divide the % of each atoms which their atomic weights.
C = 51.27 / 12 = 4.27
H = 7.75 / 1 = 7.75
O = 40.98 / 16 =2.56
Step 2 : Divide all the answers with the smallest answer to get the subscripts for empirical formula.
C = 4.27/ 2.56 ≈ 2
H = 7.75/ 2.56 ≈ 3
O = 2.56 /2.56 = 1
Step 3: Construction of empirical formula by putting subscripts calculated in step 2.
Empirical formula form given data = 
Thus , subscript for H in the empirical formula for this compound is 3.
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Answer:
For the most part, non-metals (excluding Nobel gases) are the most likely to form covalent bonds. Pure covalent bonds are formed between atoms with the same electronegativity, ie. they are trying to hold on to the electrons in the bond with the same strength.