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Gwar [14]
3 years ago
10

THANKS IN ADVANCE!

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

(1)negative x (2)negative = positive x (3)negative = negative x (4)positive = negative

negative divided by negative = positive


odd number were negative


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How many ways are there to put 6 balls in 3 boxes if the balls are distinguishable but the boxes are not?
FromTheMoon [43]

This is essentially asking how many different ways to partition 6 into 3 segments.


I am assuming "no ball in a box" is not allowed.


6 can be partitioned as

(4,1,1), (3,2,1), and (2,2,2)


So, calculate each partition, we get

(6 choose 4) + (6 choose 3)*(3 choose 2) + (6 choose 2) * (4 choose 2)

= 15 + 20*3 + 15*6

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Answer:

<h3>★ <u>11/30</u> is the right answer. ★</h3>

Step-by-step explanation:

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3 years ago
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Setler [38]

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8 0
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Read 2 more answers
36in rounded to the nearest tenth for circumference
WITCHER [35]

Answer: Remember that the tens place is two moves to the left of the decimal point (if it exists). To round to the nearest ten (nearest 10), we use the whole numbers place to determine whether the tens place rounds up or stays the same.

Solution steps:

Step 1: Locate and underline the tens place () and look to digit to the right (6):

36

Step 2: In this case, the digit to the right 6 is 5 or above. So, we add 1 to the tens place (). The digit(s) after the (6) are dropped. Thus, we get 40 as answer.

In short: 36 rounded to the nearest tens is 40.

Step-by-step explanation:

8 0
2 years ago
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