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Gwar [14]
3 years ago
10

THANKS IN ADVANCE!

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

(1)negative x (2)negative = positive x (3)negative = negative x (4)positive = negative

negative divided by negative = positive


odd number were negative


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Write the equation of a circle with the following pints in the picture using the completing the square method. Thanks
pantera1 [17]
So hmm notice the picture below

you have the center, and a point on the circle... all you need is the radius

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 1}}\quad ,&{{ -2}})\quad 
%  (c,d)
&({{ 3}}\quad ,&{{ -4}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\leftarrow  r

then use that radius in the circle's equation

\bf (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
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2 years ago
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sweet-ann [11.9K]

Answer:

4

Step-by-step explanation:

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20/2=10

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7 0
2 years ago
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Inessa [10]

Answer: yes

Step-by-step explanation:

8 0
2 years ago
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If two lines are perpendicular describe the relationship between their slopes
Aloiza [94]
Perpendicular lines have slopes that are negative reciprocals. example: line a has a slope of 2/3, line b has a slope if -3/2 if they are perpendicular.
7 0
3 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
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