The maximum torque that can act on the loop is 7.875 N-m.
Torque:
Torque is a twisting or turning force that tends to cause rotation around an axis, which might be a center of mass or a fixed point. Torque can also be thought of as the ability of something that is rotating, such as a gear or a shaft, to overcome turning resistance.
The formula of torque:
Torque(T) = I B A
B = magnetic field of intensity
I = current =
A = area of the wire
l = length of the wire
l = 2πr
r = l/2π
A = πr²
= π(l/2π)²
= l²/4π
T = l²/4π IB
=( 1/4π) BIl²
= (1/4π) 0.30 × 150 ×× 2.20
= 7.875 N-m
Therefore the torque is 7.875 N-m.
To know more about the Torque refer to the link given below:
brainly.com/question/1691855
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Answer:
v₁ = 1 [m/s].
Explanation:
This problem can be solved by using the principle of conservation of linear momentum. Where momentum is conserved before and after catching the snowball.
where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
As the momentum is conserved, it will be the same as that received by the person who catches the snowball.
That is, the person who catches the snowball moves backwards with a speed of 1 [m/s].
Answer:
ma= ma
m⋅a = m⋅a
And equivalently:
am=ma
a⋅m = m⋅a
Explanation:
Question
Assuming this question "Similar to what you see in your textbook, you can generally omit the multiplication symbol as you answer questions online, except when the symbol is needed to make your meaning clear. For example, 1*10^5 is not the same as 110^5 . When you need to be explicit, type * (Shift + 8) to insert the multiplication operator. You will see a multiplication dot (⋅) appear in the answer box. Do not use the symbol x. For example, for the expression ma,
typing m⋅a would be correct, but mxa would be incorrect".
Solution to the problem
For this case we want to write a expression for ma, and based on the previous info we can write:
ma= ma
m⋅a = m⋅a
And equivalently:
am=ma
a⋅m = m⋅a
But is not correct do this:
mxa=mxa
axm = mxa
Answer:
Your answer will be C. 3.8 kPa.