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2 years ago

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I have to choose the statement that is NOT always true: For a rhombus________________.. . A. each diagonal bisects a pair of opp

osite angles . B. All four sides are congruent. C. The diagonals are congruent. D. the diagonals are perpendicular. . I think its B.

1 answer:

nexus9112 [7]2 years ago

8 0

"For a rhombus the diagonals are congruent" is the statement among the following choices given in the question that is not always true. The correct option among all the options that are given in the question is the third option or the penultimate option or option "C". I hope the answer has come to your help.

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Answer:

900%

Step-by-step explanation:

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2 years ago

What is the maximum number of relative extrema a polynomial function can have?

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3 years ago

Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y

koban [17]

$\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}$

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3 years ago

Which of the following numbers are divisible by 3? 225, 8,399, 7,392, 9,830 (can be more than one answer) I'm very busy so I jus

soldier1979 [14.2K]

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2 years ago

Read 2 more answers

Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7

Lapatulllka [165]

The first equation is $y-2x+1=0$

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The second equation is $4x^{2}+3y^{2}-2xy=7$ (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

$4x^{2}+3(2x-1)^{2}-2x(2x-1)=7$

$4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7$

by simplifying the given equation,

$12x^{2}-10x-4=0$

$6x^{2}-5x-2=0$

Using discriminant formula,

$D=b^{2}-4ac$

$D=25-4 \times 6 \times -2 = 73$

Now the formula for solution 'x' of quadratic equation is given by:

$x=\frac{-b+\sqrt{D}}{2a} and x=\frac{-b-\sqrt{D}}{2a}$

$x=\frac{5+\sqrt{73}}{12} and x=\frac{5-\sqrt{73}}{12}$

Hence, these are the required solutions.

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3 years ago