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Snowcat [4.5K]
4 years ago
7

The calculation of kinetic energy uses the formula, KE = 1 2 mv2. Identify the unit that is required for mass and velocity, resp

ectively, to determine the kinetic energy in Joules. A) mass in g, velocity in m s B) mass in kg, velocity in m s C) mass in g, velocity in km hr D) mass in kg, velocity in km hr
Physics
2 answers:
shusha [124]4 years ago
8 0

So the answer  is B.  because the mass have  Kg as a international unit and velocity is m/s, they are  international units in physics.

kompoz [17]4 years ago
4 0

Answer:

Mass : kg

Velocity : m/s

Explanation:

Kinetic energy is due to the motion of an object. The mathematical expression for the kinetic energy is given by :

E_k=\dfrac{1}{2}mv^2

Where

m is the mass of the object

v is the velocity of object  

The SI unit of kinetic energy is joule (J). One joule equals :

E_k=\dfrac{1}{2}\times kg\times m/s=Joule

Every physical quantity must be in SI units So, mass must be in kilogram (kg) and velocity must be in meter/second (m/s).

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In a basketball game, a player shoots a jump shot. What force actually causes the player to jump into the air? Question 3 option
Julli [10]

Option B is the correct answer.

In a basketball game, a player shoots a jump shot then the floor pushes up on the player.

<h3>Newton's Third Law</h3>

Newton's third law states that when two bodies interact with each other, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction.

In the given situation, a player shoots a jump shot. It means that the player pushes the floor downward direction.

Newton's third law is applicable in this situation where the player pushes the floor downward direction, at the same time the floor pushes the player upward. The amount of force applied to the floor by the player is equal in magnitude and opposite in direction as compared to the force applied to the player by the floor.

Hence the option B is the correct answer.

To know more about Newton's third law, follow the link given below.

brainly.com/question/974124.

6 0
3 years ago
Explain how polarization of a cell increases the cell's internal resistance.<br>(2<br>2.​
Mandarinka [93]

Answer:

Explanation: The chemical action that occurs in the cell while the current is flowing causes hydrogen bubbles to form on the surface of the anode. This action is called POLARIZATION. Some hydrogen bubbles rise to the surface of the electrolyte and escape into the air, some remain on the surface of the anode. If enough bubbles remain around the anode, the bubbles form a barrier that increases internal resistance. When the internal resistance of the cell increases, the output current is decreased and the voltage of the cell also decreases.

   A cell that is heavily polarized has no useful output. There are several methods to prevent polarization or to depolarize the cell.

   One method uses a vent on the cell to permit the hydrogen to escape into the air. A disadvantage of this method is that hydrogen is not available to reform into the electrolyte during recharging. This problem is solved by adding water to the electrolyte, such as in an automobile battery. A second method is to use material that is rich in oxygen, such as manganese dioxide, which supplies free oxygen to combine with the hydrogen and form water.

   A third method is to use a material that will absorb the hydrogen, such as calcium. The calcium releases hydrogen during the charging process. All three methods remove enough hydrogen so that the cell is practically free from polarization.

LOCAL ACTION

   When the external circuit is removed, the current ceases to flow, and, theoretically, all chemical action within the cell stops. However, commercial zinc contains many impurities, such as iron, carbon, lead, and arsenic. These impurities form many small electrical cells within the zinc electrode in which current flows between the zinc and its impurities. Thus, the chemical action continues even though the cell itself is not connected to a load.

   Local action may be prevented by using pure zinc (which is not practical), by coating the zinc with mercury, or by adding a small percentage of mercury to the zinc during the manufacturing process. The treatment of the zinc with mercury is called amalgamating (mixing) the zinc. Since mercury is many times heavier than an equal volume of water, small particles of impurities weighing less than mercury will float to the surface of the mercury. The removal of these impurities from the zinc prevents local action. The mercury is not readily acted upon by the acid. When the cell is delivering current to a load, the mercury continues to act on the impurities in the zinc. This causes the impurities to leave the surface of the zinc electrode and float to the surface of the mercury. This process greatly increases the storage life of the cell.

6 0
3 years ago
Weather changes occur primarily because of
OleMash [197]
<span>Weather occurs primarily due to air pressure, temperature and moisture differences between one place to another. Therefore, the correct answer that would best complete the given statement above would be second option. </span>Weather changes occur primarily because of <span>heat exchange between the sun and atmosphere. Hope this helps.</span>
6 0
3 years ago
Read 2 more answers
Can someone help me solve these two equations?
miskamm [114]

Answer:

1a. 0.030 s

1b. 15×10¹⁰ kg m²/s²

Explanation:

Remember order of operations (PEMDAS).

1a. T_{s} =2\pi \sqrt{\frac{4.5\times10^{-2}\ kg }{2.0\times10^{3}\ kg/s^{2} } }

Start by dividing the numbers, the powers of 10 (using exponent rules), and the units.

T_{s} =2\pi \sqrt{\frac{4.5}{2.0} \frac{10^{-2}}{10^{3}} \frac{kg}{kg/s^{2}}}\\T_{s} =2\pi \sqrt{2.25 \times10^{-2-3}\ s^{2}}\\T_{s} =2\pi \sqrt{2.25 \times10^{-5}\ s^{2}}

Take the square root:

T_{s} =2\pi \sqrt{2.25} \sqrt{10^{-5}} \sqrt{s^{2}}\\T_{s} =2\pi \times1.5 \times10^{-2.5}\ s

Finally, multiply (you'll need a calculator):

T_{s} \approx 0.030\ s

1b. K=\frac{1}{2} (6.6\times10^{2}\ kg)(2.11\times10^{4}\ m/s)^{2}

Start by squaring the last term:

K=\frac{1}{2} (6.6\times10^{2}\ kg)(2.11^{2}\times10^{4\times2}\ m^{2}/s^{2})\\K=\frac{1}{2} (6.6\times10^{2}\ kg)(4.4521\times10^{8}\ m^{2}/s^{2})

Now like before, multiply the numbers, the powers of 10 (using exponent rules), and the units:

K=\frac{1}{2} (6.6\times4.4521)(10^{2+8})(kg\ m^{2}/s^{2})\\K=\frac{1}{2} (29.38386)(10^{10})(kg\ m^{2}/s^{2})\\K\approx15\times10^{10}\ kg\ m^{2}/s^{2}

8 0
3 years ago
Show all your work clearly on the scratch paper) Two in-phase loudspeakers that emit sound with the same frequency are placed al
Darya [45]

Answer:

Explanation:

The speed of sound in air to be 343 m/s.

Given:

distance 'd' = 5 m

L = 12 m

It can be concluded that path difference must be equal to half of the wavelength when person is observing destructive interference'y' at 1 m distance from the equidistant position

Since

λ/2 = yd/L

λ/2 = (1 x 5)/12

λ = 0.833m

Frequency of the sound is given by,

f = v / λ => 343 / 0.833

f=411.6 Hz

8 0
3 years ago
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