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jek_recluse [69]
2 years ago
13

A person driving a car suddenly applies the brakes. The car takes 4 s to come to rest while traveling 20 m at constant accelerat

ion. Can the speed of the car immediately before the brakes were applied be determined without first determining the car’s acceleration?
Physics
1 answer:
Zinaida [17]2 years ago
7 0

Answer:

Yes we can find the initial velocity of car without finding acceleration.

u = 10 m/s.

Explanation:

Given that

s=20 m

Car takes 4 s to come in rest.

We know that when acceleration is constant then we can apply motion equation

v=u+at        ----------1

s=ut+\dfrac{1}{2}at^2       ------2

From equation 1 and 2

s=ut+\dfrac{1}{2}t^2\left (\dfrac{v-u}{t} \right )

So we can say that

s= \left(\dfrac{v+u}{2}\right)t

Given that the velocity of car at final condition will be zero (v=0)

s= \left(\dfrac{0+u}{2}\right)t

s= \left(\dfrac{u}{2}\right)t

From the above equation we can find the initial velocity of car without finding the acceleration

20= \dfrac{u}{2}\times 4

u = 10 m/s

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f = ma

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a =  \frac{f}{m}
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a =  \frac{325}{250}
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A 100 kg box sits on an incline held at rest by a very thin rope attached to another mass hanging as shown. The force of frictio
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If friction is acting along the plane upwards

then in this case we will have

For equilibrium of 100 kg box on inclined plane we have

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also for other side of hanging mass we have

T = Mg = 50(9.8) = 490 N

now we have

100(9.8)sin\theta = 100 + 490

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sin\theta = 0.602

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In other case we can assume that friction will act along the plane downwards

so now in that case we will have

mgsin\theta + F_f = T

also we have

T = Mg = 50(9.8) N

now we have

100(9.8)sin\theta + 100 = 50(9.8)

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<em>So the range of angle will be 23.45 degree to 37 degree</em>

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