Answer: 437 g C6H6
Explanation: Solution attached:
1 mole of C6H6 is equal to its molar mass 78 g C6H6.
5.6 moles C6H6 x 78 g C6H6 / 1 mole C6H6
= 437 g C6H6
Answer:
0.02 M
Explanation:
Given data:
Mass of sodium carbonate = 1.8 g
Volume of water = 862 cm³ (862/1000 = 0.862 L)
Concentration = ?
Solution:
Formula:
Concentration = number of moles / volume in L
Number of moles of sodium carbonate:
Number of moles = mass/molar mass
Number of moles = 1.8 g/ 106 g/mol
Number of moles = 0.02 mol
Concentration:
c = 0.02 mol / 0.862 L
c = 0.02 M
Answer: change
Explanation:
Change is change and sometimes it can be good and sometimes it can be bad.