Answer:
2.53 L is the volume of H₂ needed
Explanation:
The reaction is: C₁₈H₃₀O₂ + 3H₂ → C₁₈H₃₆O₂
By the way we can say, that 1 mol of linolenic acid reacts with 3 moles of oxygen in order to produce, 1 mol of stearic acid.
By stoichiometry, ratio is 1:3
Let's convert the mass of the linolenic acid to moles:
10.5 g . 1 mol / 278.42 g = 0.0377 moles
We apply a rule of three:
1 mol of linolenic acid needs 3 moles of H₂ to react
Then, 0.0377 moles will react with (0.0377 . 3 )/1 = 0.113 moles of hydrogen
We apply the Ideal Gases Law to find out the volume (condition of measure are STP) → P . V = n . R . T → V = ( n . R .T ) / P
V = (0.113 mol . 0.082 L.atm/mol.K . 273.15K) 1 atm = 2.53 L
Answer:
Fe(NO₃)₃ + 3KSCN → Fe(SCN)₃ + 3KNO₃
Explanation:
Chemical equation:
Fe(NO₃)₃ + KSCN → Fe(SCN)₃ + KNO₃
Balanced Chemical equation:
Fe(NO₃)₃ + 3KSCN → Fe(SCN)₃ + 3KNO₃
Type of reaction:
It is double displacement reaction.
In this reaction the anion or cation of both reactants exchange with each other. In given reaction the cation Fe⁺³ exchange with cation K⁺.
The given reaction equation is balanced so there are equal number of atoms of each elements are present on both side of equation and completely hold the law of conservation of mass.
Double replacement:
It is the reaction in which two compound exchange their ions and form new compounds.
AB + CD → AC +BD
Answer: $0.48
Explanation: $1.60×0.30= 0.48
Answer:
Explanation:
Given data:
Mass of N₂ = 48.7 g
Moles of N₂ = ?
Molecules of N₂ = ?
Mass of N₂O = ?
Moles of N₂O = ?
Atoms of N₂O = ?
Solution:
Chemical equation:
2N₂ + O₂ → 2N₂O
Number of moles of N₂:
Number of moles = mass/ molar mass
Number of moles = 48.7 g / 28 g/mol
Number of moles = 1.74 mol
Number of molecules of N₂:
1 mole = 6.022 × 10²³ molecules
1.74 mol× 6.022 × 10²³ molecules/1 mol
10.5 × 10²³ molecules
Now we will compare the moles of N₂ with N₂O from balance chemical equation:
N₂ : N₂O
2 : 2
1.74 : 1.74
Moles of N₂O:
1.74 mol
Mass of N₂O:
Mass = number of moles × molar mass
Mass = 1.74 mol × 44 g/mol
Mass = 76.56 g
