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maks197457 [2]
3 years ago
14

Consider a three sequentially stepped process named as Process A, Process B and Process C. Input comes into Process A. Output fo

rm A goes into Process B. Output from B goes into Process C. Output of C is the final output. Suppose that it takes 2 minutes per unit in Process A, 3 minutes per unit in Process B and 1 minute per unit in Process C. Suppose further that Process A receives input at the rate of 30 per hour. Where would you place a buffer?
Chemistry
1 answer:
weqwewe [10]3 years ago
3 0

Answer:B the buffer will be placed in process B

Explanation:

Buffer is the extra time added to a time estimate to keep a project on track. Since process B takes a longer time to process, the buffer will be added to prevent unforseen situations.

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A piece of sodium metal can be described as?
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Answer:

A piece of sodium metal can be described as a pure substance and an element. ... Sodium is a soft, waxy, silvery, highly reactive metal. Sodium belongs to group 1 of the periodic table and it is highly abundant in the earth's crust. Sodium can also be found in various minerals such as rock salt, feldspars and sodalite.

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Help me please!
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Required number is the vertical coordinate of the intersection point of a line at 60°C with the graph of the KNO₃.

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In aqueous solution, hypobromite ion, BrO-, reacts to produce bromate ion, BrO3 -, and bromide ion, Br-, according to the follow
maw [93]

Answer:

22.73s

Explanation:

The reaction is a second order reaction, we know this by observing the unit of the slope.

rate constant = k = 0.056 M-1s-1

the initial concentration of BrO- [A]o = 0.80 M

time = ?

Final concentration [A]t= one-half of 0.80 M = 0.40M

1 / [A]t = kt + 1 / [A]o

1 / 0.40 = 0.056 * t + 1 / 0.80

t = (2.5 - 1.25) / 0.056

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5 0
3 years ago
You need to make 10 mL of 2 mg/ml solution of protein and you have 25 mg/mL solution. How much protein solution and water do you
meriva

Answer:

0.8 mL of protein solution, 9.2 mL of water

Explanation:

The dilution equation can be used to relate the concentration C₁ and volume V₁ of the stock/undiluted solution to the concentration C₂ and volume V₂ of the diluted solution:

C₁V₁ = C₂V₂

We would like to calculate the value for V₁, the volume of the inital solution that we need to dilute to make the required solution.

V₁ = (C₂V₂) / C₁ = (2mg/mL x 10mL) / (25 mg/mL) = 0.8 mL

Thus, a volume of 0.8 mL of protein solution should be diluted with enough water to bring the total volume to 10 mL. The amount of water needed is:

(10 mL - 0.8 mL) = 9.2 mL

6 0
3 years ago
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