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iris [78.8K]
3 years ago
9

4. Peter participated in a 5 K race and finished the race in 17 min. A 5k race is

Mathematics
1 answer:
juin [17]3 years ago
4 0

Answer: are you sure these are correct?

Step-by-step explanation:

You would calculate the speed be doing 5000 m / 17 min, which would be 294.117647059 m/min

17 minutes is extremely fast, but this is correct.

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A piece of land is 20cm by 5cm. A portion of the land by size 10cm by 2cm was used to cultivate tomatoes. what is the area of th
Sergio039 [100]

Answer:

80cm^2

Step-by-step explanation:

20*5=100

10*2=20

100-20=80

8 0
3 years ago
Write an expression that represents the perimeter of the football field. Let x represent the length of the football field. Inclu
dlinn [17]
Expression with parenthesis: = 2 ( l + w)
Expression without parenthesis = 2l + 2w

The property we used is known as "Distributive Property"

Let, width = w
Length = w + 70

Perimeter would be: P = 2(w+70+w)
p = 2(2w+70)
p = 4w + 140

Hope this helps!
6 0
3 years ago
Find the distance between the points (0,2)and (-5,-9)The answer must be a whole number or a fully simplified radical expression
LiRa [457]

Answer:

d = \sqrt{146}

Step-by-step explanation:

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(-5-0)^2+(-9-2)^2}\\d= \sqrt{(-5)^2+(-11)^2}\\d= \sqrt{25+121}\\d= \sqrt{146}

7 0
3 years ago
A fast food restaurant sells two sizes of fries, small and large. On Friday they sold 24 fries
mihalych1998 [28]

Answer:

5:1

Step-by-step explanation:

So, we know that 20 fries were large, and 4 were small. So, we just set it up as 20:4 <em>(for every 20 large fries, there are 4 small ones)</em>. However, it needs to be simplified which results in 5:1.

Hope I helped!!

7 0
2 years ago
Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor
docker41 [41]

Given:

The table of values is

Number of Students   :  7    14   21    28

Number of Textbooks : 35  70  105  140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

\dfrac{35}{7}=5

\dfrac{70}{14}=5

\dfrac{105}{21}=5

\dfrac{140}{28}=5

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

\dfrac{y}{x}=k

Here, k=5.

\dfrac{y}{x}=5

y=5x

Hence the rate of change is constant that is 5.

8 0
3 years ago
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