Answer:
a= - 0.79 m/s²
Explanation:
Given that
Speed ,u = 20 mi/h
We know that
1 mi/h= 0.44 m/s
Therefore ,u = 8.94 m/s
Distance ,s= 50 m
Lets take the acceleration of the car = a m/s²
The final speed of the car ,v = 0 m/s
We know that
v²= u² + 2 a s
Now by putting the values
0²= 8.94² + 2 x a x 50

a= - 0.79 m/s²
Therefore the acceleration will be - 0.79 m/s².
Explanation:
Correct option is
B
−3m/s
2
Given,
m=10kg
u=10m/s
v=−2m/s
t=4sec
The acceleration is rate of change of velocity,
a=
t
v−u
a=
4
−2−10
a=
4
−12
=−3m/s
2
The correct option is B.
Answer:
the answer is 1500 because of the internet