All categories

4 years ago

43.278 kg - 28.1 g use significant figures rule

1 answer:

3 0

You cannot directly subtract the given values because their units are different. To be consistent, let's convert kilograms to grams with the conversion that 1,000 g = 1 kg.

43.278 kg(1,000 g/1 kg) - 28.1 g = 43249.9 grams

In subtraction, you will base the number of significant figures to the least of the given data. Since 28.1 has 3 significant figures, the answer should also contain 3 significant figures. Thus, it is much more convenient to report it in terms of kilograms.

43249.9 grams * 1 kg/ 1,000 g = 43.2 kg

You might be interested in

List 3 things that magnetism and static electricity have in common

DiKsa [7]

Answer:

1. Static electricity has two charges magnetism has two poles.

2. Same charges and same poles repel and opposite charges and poles attract.

3. Static electricity is produced by charges(at rest) Magnetism is produced by charges(moving with uniform speed)

4 0

4 years ago

An object of mass 0.50 kg is transported to the surface of Planet X where the object's weight is measured to be 20 N. The radius

vovangra [49]

Explanation:

The free fall acceleration is:

F = ma

20 N = (0.50 kg) a

a = 40 m/s²

The mass of Planet X is:

F = GMm / r²

20 N = (6.67×10⁻¹¹ Nm²/kg²) M (0.50 kg) / (4.0×10⁶ m)²

M = 9.6×10²⁴ kg

5 0

3 years ago

To measure the internal diameter of a beaker one would reliably use______.

erik [133]

Answer:

Vernier calipers is used to measure the internal diameter of a beaker

3 0

3 years ago

a chuck wagon with an initial velocity of 4 m/s and a mass of 35 kg gets a push with 350 joules of force. what is the wagon's fi

Kitty [74]

Answer:

the final velocity of the wagon is 6 m/s.

Explanation:

Given;

initial velocity of the wagon, u = 4 m/s

mass of the wagon, m = 35 kg

energy applied to the wagon, E = 350 J

The final velocity of the wagon is calculated as;

E = ¹/₂m(v² - u²)

$m(v^2-u^2) = 2E\\\\v^2-u^2 = \frac{2E}{m} \\\\v^2 = \frac{2E}{m} + u^2\\\\v = \sqrt{\frac{2E}{m} + u^2} \\\\v = \sqrt{\frac{2(350)}{35} + (4)^2}\\\\v = 6 \ m/s$

Therefore, the final velocity of the wagon is 6 m/s.

8 0

3 years ago

If a girl walks 6km due west changes directions and walk another 5km due north. Find her displacement in both magnitude and dire

xenn [34]

Answer:

the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.

Explanation:

Given;

6km due west, and

5km due north

The magnitude of her displacement is calculated by forming a right angled triangle. The hypotenuse side of the triangle is the girl's displacement.

d² = 5² + 6²

d² = 25 + 36

d² = 61

d = √61

d = 7.81 m

The direction of the girl is calculated as;

$tan \ \theta = \frac{6}{5} \\\\tan \ \theta = 1.2\\\\\theta = tan^{-1} (1.2)\\\\\theta = 50.2^0$

Therefore, the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.

4 0

3 years ago