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Yuri [45]
3 years ago
10

What is the longest wavelength in the molecule’s fluorescence spectrum?

Physics
2 answers:
Darina [25.2K]3 years ago
6 0
The correct answer should be 689 nm
lisov135 [29]3 years ago
4 0

Radiation emitted can also have the same wavelength as absorbed radiation, the term "resonant fluorescence".

<h2>Further explanation </h2>

Fluorescence is the emission of light by a substance that has absorbed light or other electromagnetic radiation. Fluorescence is a form of luminescence. In some cases, the light emitted has longer waves and less energy than the absorbed radiation. Even so, when electromagnetic radiation is absorbed so much, it can be that one electron absorbs two photons; absorption of these two photons can encourage radiation with a wave that is shorter than the absorbed radiation.

The most striking example of fluorescence occurs when the absorbed radiation is in the ultraviolet spectrum, so that the human eye is not visible, and the light emitted is in the visible spectrum.

Fluorescence is widely used, including in the fields of mineralogy, gemology, chemical sensors (fluorescence spectroscopy), fluorescent marking, staining, biological detectors, and of course fluorescent lamps.

Understanding of the effects of radiation fluorescence on matter is getting deeper along with the rapid development of technology, especially in the fields of solids, light, experimental materials, data processing, measurement, and others. If the solid is observed at the smallest size (atomic), in the fluorescence effect there is an area of ​​luminescence of light or heat which can be widely used for the examination or measurement of radiation-absorbing doses. An example of the most recent use of the effect of fluorescence is to reduce exposure to X-ray radiation in health checks. Next will be explained about the theory of the effects of radiation fluorescence, characteristics, and examples of their use in the measurement of radiation absorption dose.

Learn more

resonant fluorescence brainly.com/question/3707544

wavelength brainly.com/question/3669889

Details

Grade: High School

Subject: Physics

Keyword: wavelength, fluorescence, resonant

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A 2.74 g coin, which has zero potential energy at the surface, is dropped into a 12.2 m well. After the coin comes to a stop in
VikaD [51]

Answer:

B. - 0.328

Explanation

Potential Energy:<em> This is the energy of a body due to position.</em>

<em>The S.I unit of potential energy is Joules (J).</em>

<em>It can be expressed mathematically as</em>

<em>Ep = mgh........................... Equation 1</em>

<em>Where Ep = potential energy, m = mass of the coin, h = height, g = acceleration due to gravity,</em>

<em>Given: m = 2.74 g = 0.00274 kg, h = 12.2 m, g = 9.8 m/s²</em>

Substituting these values into equation 1

Ep = 0.00274×12.2×9.8

Ep = 0.328 J.

Note: Since the potential energy at the surface is zero, the potential Energy with respect to the surface = -0.328 J

The right option is B. - 0.328

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3 years ago
Which one of the risk factors that influence you learn how may be most difficult to control as a young teen
nalin [4]
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8 0
3 years ago
A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net = 4.444 N
Dmitriy789 [7]

Answer:

The value of third charge is 0.8μC.

Explanation:

Given that.

Magnitude of net force=4.444 N

According to figure,

Suppose, First charge = 2.4 μC

Second charge = 6.2 μC

Distance r₁ = 9.8 cm

Distance r₂ = 2.1 cm

We need to calculate the value of r

Using Pythagorean theorem

r=\sqrt{(r_{1})^2+(r_{2})^2}

Put the value into the formula

r=\sqrt{(9.8)^2+(2.1)^2}

r=10.02\ cm

We need to calculate the force

Using formula of force

F_{12}=\dfrac{kq_{1}q_{2}}{(r)^2}

Force F₁₂,

F_{12}=\dfrac{9\times10^{9}\times2.4\times10^{-6}\times6.2\times10^{-6}}{(10.02\times10^{-2})^2}

F_{12}=13.33\ N

F_{21}=-13.33\ N

Force F₂₃,

F_{23}=\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(10.02)^2}

We need to calculate the value of third charge

F_{net}=F_{21}+F_{23}

4.444=-13.33+\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(5.01)^2}

q_{3}=\dfrac{(4.444+13.33)\times(5.01\times10^{-2})^2}{9\times10^{9}\times6.2\times10^{-6}}

q_{3}=7.99\times10^{-7}\ C

q_{3}=0.8\times10^{-6}\ C

Hence, The value of third charge is 0.8μC.

4 0
3 years ago
A 75 W lightbulb is being run on a 110 V outlet. Determine the resistance of the lightbulb. Provide a detailed description of th
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Power is defined as

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PLEASE ANSWER ILL GIVE YOU BRAIN
steposvetlana [31]
1:4
2:44 minutes
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