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Arte-miy333 [17]
3 years ago
6

Matthew is waterskiing. As the boat starts moving, he is at an angle of 8.0° to the right of the boat. The boat applies 250 newt

ons over the first
50 meters, while the angle stays at roughly 8.0°. What work has the boat done on Matthew
A 1.0 x 104 joules
B. 1.2 x 104 joules
C 1.4 x 10^ joules
D. 1.7 x 10^ joules
Physics
1 answer:
Citrus2011 [14]3 years ago
5 0

The work done is B. 1.2\cdot 10^4 J

Explanation:

The work done by a force on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the boat in this problem, we have:

F = 250 N (force applied)

d = 50 m (displacement)

\theta=8.0^{\circ}

Substituting, we find the work done:

W=(250)(50)(cos 8^{\circ})=1.2\cdot 10^4 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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Saturated steam at 125 kpa is compressed adiabatically in a centrifugal compressor to 700 kpa at the rate of 2.5 kg⋅s−1. the com
Tpy6a [65]
M° = 2.5 kg/sec
For saturated steam tables
at p₁ = 125Kpa
hg = h₁ = 2685.2 KJ/kg
SQ = s₁ = 7.2847 KJ/kg-k
for isotopic compression
S₁ = S₂ = 7.2847 KJ/kg-k
at 700Kpa steam with S = 7.2847
h₂ 3051.3 KJ/kg
Compressor efficiency
h =  0.78
0.78 = h₂ - h₁/h₂-h₁
0.78 = h₂-h₁ → 0.78 = 3051.3 - 2685.2/h₂ - 2685.2
h₂ = 3154.6KJ/kg
at 700Kpa with 3154.6 KJ/kg
enthalpy gives
entropy S₂ = 7.4586 KJ/kg-k
Work = m(h₂ - h₁) = 2.5(3154.6 - 2685.2
W = 1173.5KW
5 0
3 years ago
WILL MARK BRAINIEST!!!!!! (Fill in the blanks with the possible answers at the bottom)
Svetllana [295]

Answer:

Yet Yeet and Yeeeeeet

Explanation:

4 0
3 years ago
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HURRY PLEASE!!!!!
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Who conducted the study?

Explanation:

One good question to ask the toothpaste making company is who conducted the study?

A company making toothpaste claiming a scientific study revealed that their toothpaste makes the mouth five times cleaner must have introduced a bias in this finding.

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7 0
3 years ago
Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a −80-nC charge at x = −4 m on
disa [49]

Answer:

V = 48 Volts

Explanation:

Since we know that electric potential is a scalar quantity

So here total potential of a point is sum of potential due to each charge

It is given as

V = V_1 + V_2 + V_3

here we have potential due to 50 nC placed at y = 6 m

V_1 = \frac{kQ}{r}

V_1 = \frac{(9\times 10^9)(50 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_1 = 45 Volts

Now potential due to -80 nC charge placed at x = -4

V_2 = \frac{kQ}{r}

V_2 = \frac{(9\times 10^9)(-80 \times 10^{-9})}{12}

V_2 = -60 Volts

Now potential due to 70 nC placed at y = -6 m

V_3 = \frac{kQ}{r}

V_3 = \frac{(9\times 10^9)(70 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_3 = 63 Volts

Now total potential at this point is given as

V = 45 - 60 + 63 = 48 Volts

3 0
3 years ago
A car slows down from 23 m/s to rest in a distance of 85 m. what was its acceleration, assmed constant
enyata [817]

First calculate the time by using following equation:<span>
d= (vi+vf)/2 x t </span>

where t = time

vi is the initial velocity = 23 m/s

<span>vf is the final velocity  = 0 m/s</span>

and d is the distance covered = 85m

85 = (23 + 0)/2 x t

t = 85/11.5 = 7.39s

Now use this equation to find acceleration:

a= (vf-vi)/t <span>

a = 0 – 23/ 7.39</span>

a = -3.112 m/s²

<span>so, the acceleration is 3.112 m/s</span>²<span>


</span>

6 0
3 years ago
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