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Arte-miy333 [17]
3 years ago
6

Matthew is waterskiing. As the boat starts moving, he is at an angle of 8.0° to the right of the boat. The boat applies 250 newt

ons over the first
50 meters, while the angle stays at roughly 8.0°. What work has the boat done on Matthew
A 1.0 x 104 joules
B. 1.2 x 104 joules
C 1.4 x 10^ joules
D. 1.7 x 10^ joules
Physics
1 answer:
Citrus2011 [14]3 years ago
5 0

The work done is B. 1.2\cdot 10^4 J

Explanation:

The work done by a force on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the boat in this problem, we have:

F = 250 N (force applied)

d = 50 m (displacement)

\theta=8.0^{\circ}

Substituting, we find the work done:

W=(250)(50)(cos 8^{\circ})=1.2\cdot 10^4 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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the answer is letter; C

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Sammy squirrel is steering his boat at a heading of 327 degree at 18mph. The current is flowing at 4mph at a heading of 60 degre
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Answer:

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Explanation:

To find Sammy's course you have to add the two velocities (vectors), 18 mph 327º and 4 mph 60º.

To add the two vectors analytically you decompose each vector into their vertical and horizontal components.

<u>1. 18 mph 327º</u>

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  • Vertical component: 18 mph × sin (327º) = - 9.80 mph

  • Vector notation:

       15.10\hat i-9.80\hat j

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  • Vertical component: 4 mph × sin (60º) = 3.46 mph

  • Vector notation:

       2.00\hat i+3.46\hat j

<u>3. Addition:</u>

You add the corresponding components:

15.10\hat i-9.80\hat j+2.00\hat i+3.46\hat j\\ \\ 17.10\hat i-6.34\hat j

To find the magnitude use Pythagorean theorem:

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<u>4. Direction:</u>

Use the tangent ratio:

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Find the inverse:

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