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Karolina [17]
3 years ago
11

Which segment of the graph represents constant speed? Explain your answer.

Physics
1 answer:
taurus [48]3 years ago
7 0

D is the answer

in V-t graph, tan α= velocity/time=acceleration

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A loudspeaker in a parked car is producing sound whose frequency is 20950 Hz. A healthy young person with normal hearing is stan
rusak2 [61]

Answer:

359 m/s

Explanation:

Highest frequency a person can hear is 20,000Hz.

f = c × λ

Frequency = Wave speed × Wavelength

Wavelength = 20,000 ÷ 343 = 58.31m

Wavespeed = Frequency ÷ Wavelength

c = 20,950 ÷ 58.31 = 359.3 m/s

= 359 m/s (3 s.f.)

3 0
3 years ago
The table below shows the average wind speeds of four hurricanes in Florida. Florida Hurricanes Hurricane | Average Wind Speed (
Anna [14]

Answer:d

Explanation:

3 0
3 years ago
Read 2 more answers
A Parachutist with a camera, with descending at a speed of 12.5m/s, releases, the camera at an altitude of 64.3m. What is the ma
jonny [76]

Given :

Initial velocity, u = 12.5 m/s.

Height of camera, h = 64.3 m.

Acceleration due to gravity, g = 9.8 m/s².

To Find :

How long does it take the camera to reach the ground.

Solution :

By equation of motion :

h = ut+\dfrac{gt^2}{2}

Putting all given values, we get :

12.5t+\dfrac{9.8t^2}{2}=64.3\\\\4.9t^2+12.5t=64.3

t = 2.56  and t = −5.116.

Since, time cannot be negative.

t = 2.56 s.

Therefore, time taken is 2.56 s.

Hence, this is the required solution.

7 0
3 years ago
Two coulombs of charge pass through a wire in 5 seconds. Calculate the current in the wire. 1​
gogolik [260]

Answer:

0.4A.

Explanation:

Current (A) = Charge (coulomb)/Time (secs)

2 coulombs/5 secs = 0.4A

7 0
2 years ago
Sound with a frequency of 1250 Hz leaves a room through a doorway with a width of 1.05 m.At what minimum angle relative to the c
kiruha [24]

Answer:

15.19°, 31.61°, 51.84°

Explanation:

We need to fin the angle for m=1,2,3

We know that the expression for wavelenght is,

\lambda = \frac{c}{f}

Substituting,

\lambda = \frac{344}{1250}

\lambda = 0.2752m

Once we have the wavelenght we can find the angle by the equation of the single slit difraction,

sin\theta = \frac{m \lambda}{W}

Where,

W is the width

m is the integer

\lambda the wavelenght

Re-arrange the expression,

\theta = sin^{-1} \frac{m\lambda}{W}

For m=1,

\theta = sin^{-1} \frac{1 (0.2752)}{1.05}= 15.19\°

For m=2,

\theta = sin^{-1} \frac{2 (0.2752)}{1.05}= 31.61\°

For m=3,

\theta = sin^{-1} \frac{3 (0.2752)}{1.05}= 51.84\°

<em>The angle of diffraction is directly proportional to the size of the wavelength.</em>

5 0
3 years ago
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