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Karolina [17]
3 years ago
11

Which segment of the graph represents constant speed? Explain your answer.

Physics
1 answer:
taurus [48]3 years ago
7 0

D is the answer

in V-t graph, tan α= velocity/time=acceleration

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At any crime scene, the two greatest challenges to the physical evidence are contamination and loss of continuity.

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7 0
2 years ago
Does this equation show that transmutation has taken place during decay?
Natalija [7]

Answer:

Maybe A is the correct answer

7 0
3 years ago
Using -10 m/s2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before h
ASHA 777 [7]
If it starts from 0m/s...
s=?
u=0
a=-10
t=8
s=ut +1/2at^2
so s=(0×8)+ (0.5×-10×64)
s=0+(32×-10)
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Which is one<br> step that geologists use to find the epicenter of an earthquake?
Kisachek [45]

Answer:

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5 0
3 years ago
Read 2 more answers
A 3.00N rock is thrown vertically into the air from the ground. At h=15.0m, v=25m/s upward. Use the work-energy theorem to find
butalik [34]

Answer:

so initial speed of the rock is 30.32 m/s

correct answer is b. 30.3 m/s

Explanation:

given data

h = 15.0m

v = 25m/s

weight of the rock m = 3.00N  

solution

we use here work-energy theorem that is express as here

work = change in the kinetic energy    ..............................1

so it can be written as

work = force × distance     ...................2

and

KE is express as

K.E = 0.5 × m × v²  

and it can be written as

F × d = 0.5 × m × (vf)² - (vi)²      ......................3

here

m is mass and vi and vf is initial and final velocity

F = mg = m  (-9.8)  , d = 15 m and v{f} = 25 m/s

so put value in equation 3 we get

m  (-9.8) × 15 = 0.5 × m × (25)² - (vi)²

solve it we get

(vi)² =  919

vi = 30.32 m/s

so initial speed of the rock is 30.32 m/s

5 0
3 years ago
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