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never [62]
3 years ago
8

A woman floats in a region of the Great Salt Lake where the water is about four times saltier than the ocean and has a density o

f about 1130 kg/m3. The woman has a mass of 52 kg, and her density is 943 kg/m3 after exhaling as much air as possible from her lungs.
1) Determine the percentage of her volume that will be above the waterline of the Great Salt Lake.
Physics
1 answer:
julsineya [31]3 years ago
3 0

To develop the problem it is necessary to use the concepts related to density and its definition with respect to mass and volume, as well

\rho= \frac{m}{V}

Therefore to calculate the volume of woman:

V = \frac{m}{\rho}\\V = \frac{52}{943}\\V = 0.0551 m^3

Now, volume of water of Great Salt Lake with the mass of 52 kg,

V_i = \frac{52}{1130} \\V_i = 0.0460 m^3

So, percentage of her volume changed will be,

\%=\frac{(V - Vi)}{V}*100\\\% = \frac{(0.0551 - 0.0460)}{0.0551}*100 \\\% == 16.51 \%\\

Therefore the percentage of her volume that will be above the waterline of the Great Salt Lake is 16.51%

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Answer:

The answer to the question is

4433.416 kJ

See explanation below

(3-y)²+r² = 3² or

6y-y² = r²

r =√(6y-y²)

The volume of a small section of height Δy =  Δy ×(√(6y-y²))²×π

For water with density of 1000 kg/m³, the mass of the slice

= 1000×Δy ×(√(6y-y²))²×π and since force = mass × acceleration we have

1000×Δy ×(√(6y-y²))²×π ×g = 1000×Δy ×(√(6y-y²))²×π ×9.81

The work done to move a unit height of y+1 = Force × Distance

W  = 1000×Δy ×(√(6y-y²))²×π ×9.81 × (y+1)

Integrating the entire section of the sphere that is 2×r high, or from 0 to 6 we get

W =\int\limits^6_0 {1000*(6y-y^{2} ) *\pi *9.81 * (y+1)} \, dy

= 9810*\pi \int\limits^6_0 {5y^{2} -y^{3}  +6y \, dy

= 9810*\pi *[\frac{5y^{3} }{3} -\frac{y^{4} }{4} +3y^{2} ]^{6} _{0}

=9810×π×144 =4433416 J

7 0
3 years ago
A sphere of radius r = 5cm carries a uniform volume charge density rho = 400 nC/m^3. Q. What is the total charge Q of the sphere
Tanzania [10]

Answer:

The total charge Q of the sphere is 2.094\times10^{-10}\ C.

Explanation:

Given that,

Radius = 5 cm

Charge density J= 400\ nC/m^3

We need to calculate the total charge Q of the sphere

Using formula of charge

q=\rho V

Where, \rho = charge density

V = volume

Put the value into the formula

q=\rho\times(\dfrac{4}{3}\pi r^3)

Put the value into the formula

q=\dfrac{4}{3}\times\pi\times400\times10^{-9}\times(5\times10^{-2})^3

q=2.094\times10^{-10}\ C

Hence, The total charge Q of the sphere is 2.094\times10^{-10}\ C.

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3 years ago
Could someone explain to me how to got the answer B, thank you very much​
Mnenie [13.5K]

Answer:

since -6 lasted for 5 seconds, multiplying both would result in -30

3 lasted for 10 seconds, so multiplying both would give +30

average = ( 30 + (-30) ) / 2

30 -30 is already equal to zero, so the answer should be 0

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During which phase of the moon can a lunar eclipse happen?.
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Full moon!

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2 years ago
Two families meet at the park at 10:00am. Each family uses a different way of transportation to get there. The Gonzalez family l
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Firstly, we need to make the times and distance equal to compare.

1hr=60mins
Gonz drove 90km in 60mins,so they would drive 45km in 30 mins dividing it by 2.
Because the Rivs had gone 30km in 30mins, Gonz were faster.

For the adverage speed, we should first add the speed of each family in mph , so 90+60, which equals 150 and divide that by 2 because there are 2 speeds so the average speed is 75mph.

P.S English is my second language so tell me if you don't understand something and I will try and explain.
5 0
3 years ago
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