Answer:
The answer to the question is
4433.416 kJ
See explanation below
(3-y)²+r² = 3² or
6y-y² = r²
r =√(6y-y²)
The volume of a small section of height Δy = Δy ×(√(6y-y²))²×π
For water with density of 1000 kg/m³, the mass of the slice
= 1000×Δy ×(√(6y-y²))²×π and since force = mass × acceleration we have
1000×Δy ×(√(6y-y²))²×π ×g = 1000×Δy ×(√(6y-y²))²×π ×9.81
The work done to move a unit height of y+1 = Force × Distance
W = 1000×Δy ×(√(6y-y²))²×π ×9.81 × (y+1)
Integrating the entire section of the sphere that is 2×r high, or from 0 to 6 we get
W =
= 
![= 9810*\pi *[\frac{5y^{3} }{3} -\frac{y^{4} }{4} +3y^{2} ]^{6} _{0}](https://tex.z-dn.net/?f=%3D%209810%2A%5Cpi%20%2A%5B%5Cfrac%7B5y%5E%7B3%7D%20%7D%7B3%7D%20-%5Cfrac%7By%5E%7B4%7D%20%7D%7B4%7D%20%2B3y%5E%7B2%7D%20%5D%5E%7B6%7D%20_%7B0%7D)
=9810×π×144 =4433416 J
Answer:
The total charge Q of the sphere is
.
Explanation:
Given that,
Radius = 5 cm
Charge density 
We need to calculate the total charge Q of the sphere
Using formula of charge

Where,
= charge density
V = volume
Put the value into the formula

Put the value into the formula


Hence, The total charge Q of the sphere is
.
Answer:
since -6 lasted for 5 seconds, multiplying both would result in -30
3 lasted for 10 seconds, so multiplying both would give +30
average = ( 30 + (-30) ) / 2
30 -30 is already equal to zero, so the answer should be 0
Full moon!
when Earth is exactly between the Moon and Sun, Earth's shadow falls upon the surface of the Moon, dimming it and sometimes turning the surface red over the course of a few hours.
Firstly, we need to make the times and distance equal to compare.
1hr=60mins
Gonz drove 90km in 60mins,so they would drive 45km in 30 mins dividing it by 2.
Because the Rivs had gone 30km in 30mins, Gonz were faster.
For the adverage speed, we should first add the speed of each family in mph , so 90+60, which equals 150 and divide that by 2 because there are 2 speeds so the average speed is 75mph.
P.S English is my second language so tell me if you don't understand something and I will try and explain.