I did a project on Wood vs aluminum baseball bats to see which ball would travel farther when hit. I don't know If you play sports or anything but it was very fun for me considering I enjoy playing the game. You just got to be able to hit a ball with a bat
<em>math</em><em>ematically</em><em>,</em>
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<em>where</em><em> </em><em>t</em><em> </em><em>=</em><em> </em><em>tim</em><em>e</em>
<em>from</em><em> </em><em>the</em><em> </em><em>q</em><em>uestion</em><em>,</em><em> </em><em>t</em><em>=</em><em> </em><em>0</em><em>.</em><em>0</em><em>7</em><em>7</em><em>s</em><em>e</em><em>c</em>
<em>sub</em><em>stitute</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>th</em><em>e</em><em> formula</em>
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<em>approximately</em><em> </em><em>1</em><em>3</em><em>s</em><em>^</em><em>-</em><em>1</em>
Answer:
Lowest resonant frequency:
Wave Speed:
Explanation:
The lowest resonant frequency
For a fixed string a resonant mode is always a integer multiple of fundamental frequency (the lowest resonant frequency):
Is the frequency for a resonant mode
is fundamental frequency (the lowest resonant frequency).
Due to problem says that there's not intermediate resonant frequencies between 684 Hz and 798 Hz, i.e, they are consecutive resonant modes, equations are as follows:
Solving for n from equation (1) and replacing it in the equation (2)
And finally solving for
Wave speed
For a fixed string the wave speed can be calculated by using
Where V is the wave speed and L is the string length.
So, using this equation and solving for V:
<em>It Is very important convert the string length unit to meters</em>
Answer:
Tension.
<em><u>tension</u></em> is the name of force that opposes or goes opposite of gravity
Hope this helps!
Answer:
<h2>
4519.60 J/K</h2>
Explanation:
Change in entropy is expressed as ΔS = ΔQ/T where;
ΔQ is the total heat change during conversion of ice to water.
T is the room temperature
First we need to calculate the total change in heat using the conversion formulae;
ΔQ = mL + mcΔθ (total heat energy absorbed during phase change)
m is the mass of ice/water = 900g = 0.9kg
L is the latent heat of fusion of ice = 3.33 x 10⁵J/kg
c is the specific heat capacity of water = 4200J/kgK
Δθ is the change in temperature of water = 10°C - 0C = 10°C = 283K
Substituting the given values into ΔQ;
ΔQ = 0.9(333000)+0.9(4200)(283)
ΔQ = 299700 + 1069740
ΔQ = 1,369,440 Joules
Since Change in entropy ΔS = ΔQ/T
ΔS = 1,369,440/30+273
ΔS = 1,369,440/303
ΔS = 4519.60 J/K
Hence, the change in entropy of the universe is 4519.60 J/K