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Kruka [31]
2 years ago
9

Can y’all help me with 5 plsssss

Physics
2 answers:
Lemur [1.5K]2 years ago
6 0

Answer:

Bar graph would work :)

Alona [7]2 years ago
4 0

Answer:

Bar graph

Explanation:

each day collects data so a bar graph would work.

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On a roller coaster, describe the kinetic and potential energy of the car at the top of the first hill, the bottom of the first
vaieri [72.5K]
The total amount of energy stays the same, but throughout the ride, the kinetic energy and the potential energy change, still adding up to the same number. At the top of the ride it has potential energy, and as it goes down the potential energy decreases and the kinetic energy increases. When it’s at the bottom of the first drop it has maxed out its kinetic energy, and minimized its potential energy. Friction slows down the car, and pushes on the cart with a force that is equal and opposite to the force being exerted in the track. The reason the track keeps going is because though it exerts and equal and opposite force the momentum of the objects is different, allowing the car to continue moving, however friction will slow it down until eventually it comes to a stop.
8 0
3 years ago
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I will mark either the best or the first as brainliest.
tankabanditka [31]
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3 years ago
You sit at the middle of a large turntable at an amusement park as it is set spinning on nearly frictionless bearings, and then
jolli1 [7]

Answer:

Decrease

Explanation:

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"When the net external torque acting on a system about a given axis is. zero , the total angular momentum of the system about that axis remains constant."

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3 years ago
Refrigerant 134a enters a well-insulated nozzle at 200 lbf/in.2, 200°F, with a velocity of 120 ft/s and exits at 50 lbf/in.2 wit
riadik2000 [5.3K]

Answer:

x = 0.75801 = 75.801%

T_2 = 72..78 degree F

Explanation:

From superheated R 134 a properties table

At 200 lb/in^2 and 200 degree F

h_1 = 138.99 Btu/lbm

steady flow energy equation is givena s

h_1 + \frac{v_1^2}{2}  = h_2 + \frac{v_2^2}{2}

138.99 + \frac{120^2}{2\times 25037} = h_2 + \frac{1500^2}{2 \times 25037}

h_2 = 94.344 Btu/lbm

At 90 lb/in2 Tsat = 72.78 degree F

h_f = 35.715 Btu/lbm

hfg  = 77.345 Btu/lbm

h = hf + x hfg

94.344 = 35.715+ x \times 77.345

solving for x we get

x = 0.75801 = 75.801%

T_2 = 72..78 degree F

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3 years ago
What s an asteroid?
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A. rocky orbiting object

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