Answer:
a) x_{cm} = m₂/ (m₁ + m₂) d
, b) x_{cm} = 52.97 pm
Explanation:
The expression for the center of mass is
= 1 / M ∑
Where M is the total masses, mI and xi are the mass and position of each element of the system.
Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon
x_{cm} = 1 / (m₁ + m₂) (0+ m₂ x₂)
Let's reduce the magnitudes to the SI system
m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg
m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg
d = 128 pm = 128 10⁻¹² m
The equation for the center of mass is
x_{cm} = m₂/ (m₁ + m₂) d
b) let's calculate the value
x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷ 128 10-12
x_{cm} = 52.97 10⁻¹² m
x_{cm} = 52.97 pm
Hello there
the answer is
Let the initial position from where the ball is kickedat angle 45 deg, be A. The Horizontal range of the ball (AC) is V2 Sin2θ / g = 38.76 Meters
thank you
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b

c

Explanation:
Considering the first question
From the question we are told that
The force produced is 
The duration of the punch is 
Generally the impulse delivered is mathematically represented as

=> 
=>
Considering the second question
The approaching velocity of the ball is 
The leaving velocity of the ball is 
The mass of the ball is 
Generally the magnitude of the impulse delivered is mathematically represented as

=> ![I_1 = [0.145 * 45] - [0.145 * -53]](https://tex.z-dn.net/?f=I_1%20%3D%20%20%5B0.145%20%2A%20%2045%5D%20%20-%20%5B0.145%20%2A%20-53%5D)
=> 
Considering the third question
The duration of the impact of the bat is 
Generally the average force exerted by the bat is mathematically represented as

=> 
=> 
Answer:
C = Q / V
Q = C * V = 2.5 F * 3 V = 7.5 Coulombs (assuming the batteries are in series)
N e = Q where N is the number of electrons and e the electronic charge
N = 7.5 / (1.60E-19) = 4.7E19 electrons
or 4.7 * 10^19 electrons