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liraira [26]
1 year ago
12

A large plate carries a uniform charge density σ = 8. 85 × 10-9 c/m2. a pattern showing equipotential surfaces with a 5 v potent

ial difference would appear as:_________
Physics
1 answer:
vfiekz [6]1 year ago
5 0

The potential difference comes out to be

10 \times 10 {}^{ - 3} m

Given:

σ = 8. 85 × 10-9 c/m2

we know,

E = \frac{σ}{2ε0}

E =  \frac{8.85 \times 10 {}^{ - 9} }{2ε0}

E =  \frac{v}{d}

given the potential difference between two equipotential surface=5v

E=∆v

∆d=∆v/E

=  \frac{5 \times 8.85 \times 10 { }^{ - 12} \times 2 }{8.85 \times 10 {}^{ - 9} }

Δ = 10 \times 10 {}^{ - 3} m

Thus the potential difference is

10 \times 10 {}^{ - 3} m

Learn more about potential difference from here: brainly.com/question/28165869

#SPJ4

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kirill115 [55]

Answer:

8100 g

Explanation:

8.1 kg × 1000

= 8100 g

6 0
3 years ago
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A certain carbon monoxide molecule consists of a carbon atom mc = 12 u and an oxygen atom mo = 17 u that are separated by a dist
kvasek [131]

Answer:

a)  x_{cm} = m₂/ (m₁ + m₂)   d , b)   x_{cm} = 52.97 pm

Explanation:

The expression for the center of mass is

                x_{cm} = 1 / M  ∑ x_{i} m_{i}

Where M is the total masses, mI and xi are the mass and position of each element of the system.

Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon

              x_{cm} = 1 / (m₁ + m₂)   (0+ m₂ x₂)

Let's reduce the magnitudes to the SI system

             m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg

             m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg

             d = 128 pm = 128 10⁻¹² m

The equation for the center of mass is

               x_{cm} = m₂/ (m₁ + m₂)   d

b) let's calculate the value

            x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷    128 10-12

            x_{cm} = 52.97 10⁻¹² m

            x_{cm} = 52.97 pm

7 0
3 years ago
A soccer ball is kicked from the ground with an initial speed of 19.3 m/s at an upward angle of 45°. a player 54.7 m away in the
dalvyx [7]

Hello there

the answer is

Let the initial position from where the ball is kickedat angle 45 deg, be A. The Horizontal range of the ball (AC) is V2 Sin2θ / g = 38.76 Meters

thank you

3 0
3 years ago
We can compare these two interactions on the basis of impulse (see above), but sometimes, we are more interested in the forces (
kiruha [24]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 I =  476 \ N \cdot s

b

 I_1 =  14.21 \  N\cdot s

c

    F  = 20300 \  N

Explanation:

Considering the first question

From the question we are told that

   The force produced is F  =  3400 \ N

   The duration of the punch is  t =  0.14 \  s

Generally the impulse delivered is mathematically represented as

    I =  F  *  t

=>    I =  3400  *  0.14

=>    I =  476 \ N \cdot s

Considering the second  question

   The approaching velocity of the ball is  v_b  =  45 \ m/s

    The leaving  velocity of the ball is  v_l  =  -53 \ m/s

     The mass of the ball is  m_b  =  0.145 \  kg

Generally the magnitude of the impulse delivered is mathematically represented as

     I_1 =  m*  v_b  - m *  v_l

=>     I_1 =  [0.145 *  45]  - [0.145 * -53]

=>     I_1 =  14.21 \  N\cdot s

Considering the third  question

     The  duration of the impact of the bat is  t _1 =  0.7 \ ms  =  0.7 *10^{-3} \  s

      Generally the average force exerted by the bat is mathematically represented as  

       F  =  \frac{I_1}{t_1}

=>     F  =  \frac{14.21 }{0.7 *10^{-3}}

=>       F  = 20300 \  N

 

7 0
3 years ago
(a) Suppose you charge a 2.5 F capacitor with two 1.5 volt batteries. How much charge was on each plate? 7.5 Correct: Your answe
natali 33 [55]

Answer:

C = Q / V      

Q = C * V = 2.5 F * 3 V = 7.5 Coulombs (assuming the batteries are in series)

N e = Q       where N is the number of electrons and e the electronic charge

N = 7.5 / (1.60E-19) = 4.7E19 electrons

or 4.7 * 10^19 electrons

7 0
2 years ago
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