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borishaifa [10]
3 years ago
11

A 34.00 kg sample of mud has a specific heat of 2,512 J/kg °C.

Physics
1 answer:
Elena-2011 [213]3 years ago
6 0

Answer:

B ig lol

Explanation:

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Your friends sit in a sled in the snow. If you apply a force pf 75 N to them, they have an acceleration of 0.9 m/s ^ 2. What is
Elza [17]

Answer:

Mass of the sled in the snow 83.33 kg.

<u>Explanation</u>:

Given that,  

Force applied to move the sled in the snow (F) = 75N

\text { Acceleration }(a)=0.9 \mathrm{m} / \mathrm{s}^{2}

We know that

Newton's second law of motion is  

\text { Force }=\text { mass } \times \text { acceleration }

F = ma (Or "force" is equal to "mass" times "acceleration".)

So if we move this around we can isolate mass and get mass

\text { Mass }=\frac{\text { force }}{\text { accelearation }}

\mathrm{M}=\frac{75}{0.9}

M = 83.33 kg

Mass of the sled in the snow <u>83.33 kg.</u>

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3 years ago
Which type of mirror produces images that are always upright and at the same distance from the mirror as the object is?
Alex73 [517]
Well, that would be a plane (flat) mirror 
<span>provided that </span>
<span>the mirror and the object are oriented parallel to each other</span>
7 0
3 years ago
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How much heat is needed to raise the temperature of 9g of water by 17oC?
andre [41]
Well the heat that is needed to raise the temperature of 10g of water by 17oC is 7
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3 years ago
A bell rings at a frequency of 75hz on a warm 25 degree evening. calculate the...
allochka39001 [22]

Answer:

Explanation:

We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.

The velocity of sound is found in:

v = 331.5 + .606T

We need to find that first in order to fill it into the frequency equation which is

f=\frac{v}{\lambda} where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:

v = 331.5 + .606(25) and

v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:

v = 347 m/s

Filling that into the frequency equation:

75=\frac{347}{\lambda} and

\lambda=\frac{347}{75} so

\lambda=4.6m

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