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Ratling [72]
3 years ago
12

The process by which wind removes surface materials is called what?

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
5 0

The process by which wind removes surface materials is called abrasion.

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Potential energy is based on an objects <br><br> A)gravity<br> B)mass<br> C)position <br> D)kinetic
ollegr [7]

Answer:

c

Explanation:

because potential energy is created with the position of a body when you pick up something the thing will have stored energy which is transferred from you so the stored energy is potential energy created by the position of a body that when you see over your head you scared of that thing not to bit you because it has stored energy if you see the thing already failed on the ground you wouldn't scared of that because the enery is already gone

Hope help you

5 0
2 years ago
Consider the above reaction. If some CO2 were removed from the container, what would the reaction do in an attempt to replace th
faltersainse [42]

Answer:

See explanation

Explanation:

The reaction to be considered is shown below;

H2CO3<------->CO2 + H2O

We know  that when a constraint such as a sudden change in concentration, pressure or temperature is imposed on  a reaction system in equilibrium, the system has to adjust itself by shifting in a particular direction in order to cancel the constraint.

Now, if we remove CO2, the equilibrium position must shift to the right by the decomposition of more H2CO3 to establish equilibrium again.

4 0
2 years ago
Why are basic radicals classified into six groups?​
Alona [7]

Basic radicals (cations) have been divided into groups based on Ksp values

4 0
2 years ago
A 4-inch, f/5 telescope has a 1-inch eyepiece focal. Its magnifying power is:
Gre4nikov [31]

Its magnifying power is: 4X 5X 9X 20X. A 4-inch, f/5 telescope has a 1-inch eyepiece focal. Its magnifying power is 9x. This answer has been confirmed as correct and helpful.

7 0
3 years ago
Read 2 more answers
When equal volumes of 0.5 M HCl and 0.5 M Ca(OH)2 are mixed, the resulting solution is
Mademuasel [1]

The concentration of mixed solution = 0.5 M

<h3> Further explanation </h3>

Given

0.5 M HCl

0.5 M Ca(OH)₂

Required

The concentration

Solution

Molarity from 2 solutions :

Vm Mm = V₁. M₁ + V₂. M₂  

m = mixed solution

V = volume

M = molarity

V = mixed volume  

1 = solution 1

2 = solution 2

Vm = V₁+V₂

Equal volumes⇒V₁=V₂, and Vm = 2V, then equation becomes :

2V.Mm = V(M₁+M₂)

2V.Mm = V(0.5+0.5)

Mm=0.5 M

8 0
2 years ago
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