It may be faith. So it faith is in your word bank then that's probably it, and if faith isn't in the word bank, then I will need to know the words that are in the word bank.
<span>Volume is a measure of the amount of space an object takes up. When a cylinder is submerged in the water it pushes water out of the way. If you measure the amount the water level increases, you can find the volume of the water pushed out of the way. </span>
Answer:
Most of these rocks are not made up of common geometric shapes
Explanation:
Because most rocks are not made up of common geometric shapes, it would be difficult or impossible to find the volume of a rock using a ruler; there would be no easy way to measure the rock's volume using a ruler
Hope this helped!
The answer is: absorbs more H (protons) ions.
- The Sodium hydroxide NaOH ionizes completely when dissolved in water.
- For every mole of sodium hydroxide that you dissolve you get 1 mole of hydroxide anions.
Answer:
![n_{C_6H_{10}}=0.03molC_6H_{10}](https://tex.z-dn.net/?f=n_%7BC_6H_%7B10%7D%7D%3D0.03molC_6H_%7B10%7D)
Explanation:
Hello,
In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:
![n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}](https://tex.z-dn.net/?f=n_%7BC_6H_%7B10%7D%7D%3D3mLC_6H_%7B12%7DO%2A%5Cfrac%7B0.9624gC_6H_%7B12%7DO%7D%7B1mLC_6H_%7B12%7DO%7D%2A%5Cfrac%7B1molC_6H_%7B12%7DO%7D%7B100.158gC_6H_%7B12%7DO%7D%2A%5Cfrac%7B1molC_6H_%7B10%7D%7D%7B1molC_6H_%7B12%7DO%7D%20%5C%5Cn_%7BC_6H_%7B10%7D%7D%3D0.03molC_6H_%7B10%7D)
Besides, the mass could be computed as well by using the molar mass of cyclohexene:
![m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}](https://tex.z-dn.net/?f=m_%7BC_6H_%7B10%7D%7D%3D0.03molC_6H_%7B10%7D%2A%5Cfrac%7B82.143gC_6H_%7B10%7D%7D%7B1molC_6H_%7B10%7D%7D%20%5C%5C%5C%5Cm_%7BC_6H_%7B10%7D%7D%3D2.4gC_6H_%7B10%7D)
Even thought, the volume could be also computed by using its density:
![V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}](https://tex.z-dn.net/?f=V_%7BC_6H_%7B10%7D%7D%3D2.4gC_6H_%7B10%7D%2A%5Cfrac%7B1mLC_6H_%7B10%7D%7D%7B0.811gC_6H_%7B10%7D%7D%20%5C%5CV_%7BC_6H_%7B10%7D%7D%3D3mLC_6H_%7B10%7D)
Best regards.