Answer:
The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.
Explanation:
The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.
<span>Ag2S
Ag(silver) has a charge of 1+
S2-(Sufide has a charge 2-
you need balance
charge have to equal to zero so you need 2 silvers and one sulfide
to have equilibrium</span>
Answer: 1.32
Explanation:
First, we must obtain the molar mass of HBr. After that, we try to obtain the concentration of the hydrobromic acid from the formula n=CV since the volume of solution and mass of acid was provided. Recall that n=m/M. If the concentration of acid is thus obtained, we make use of the fact that the concentration of H+ in the acid is equal to the molar concentration of HBr to obtain the pH. The pH is the negative logarithm of the concentration we obtained in the initial step.
This correct option is C.
10^-2 = 0.001
8.7 * 10^-2 = 8.7 * 0.001 = 0.0087
Thus, 8.7 * 10^-2 is equivalent to 0.0087.