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3 years ago

Please help balance this equation _B2Br6 + _HNO3= _B(NO3)3+_HBr

Chemistry

1 answer:

Trava [24]3 years ago

4 0

Answer: B2Br6 + 6HNO3 → 2B(NO3)3 + 6BrH

Equation

B2Br6+HNO3=B(NO3)3+HBr

B=2 B=1

BR=6 BR=1

H=1 H=1

N=1 N=3

O=3 O=9

ANSWER

B2Br6 + 6HNO3 → 2B(NO3)3 + 6BrH

B=2 B=2

BR=6 BR=6

H=6 H=6

N=6 N=6

O=18 O=18

HOPE THIS HELPS

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2 years ago

A student measures the volume of a solution to be 0.01370 l. How many significant digits are in this measurement?

Mkey [24]

A student measures the volume of a solution to be 0.01370 have 5 significant digits in this measurement.

<h3>What are significant digits?</h3>

The significant digits are the minimum number from zero to nine for reporting any measurement where the digits are uncertain.

The significant digits starting from zero are not significant digits, decimal is not a significant digit, and ending zero after the decimal are significant digits.

Therefore, the student measures the volume of a solution to be 0.01370 5 significant digits are in this measurement.

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2 years ago

What would be the major product obtained from hydroboration–oxidation of the following alkenes?

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Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore the "OH" will be added to carbon 2 producing 2-methylcyclohexan-1-ol.

See figure 1

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3 years ago

What is the proper name for Zn(CIO)2?

Sergio [31]

Answer:

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Explanation:

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3 0

3 years ago

Read 2 more answers

How many moles of nacl are required to make 250 ml of a 3.00 m solution?

choli [55]

The molarity is calculated using the following rule:
molarity = number of moles of solvent / volume of solution (in liters)

We have the volume of solution = 250 ml = 0.25 liters and the molarity = 3 m

Substituting in the equation, we get:
3 = number of moles / 0.25
number of moles = 3 x 0.25 = 0.75 moles

4 0

3 years ago