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Naily [24]
3 years ago
15

Help ;-; Will give Brainliest and 25 Points

Chemistry
2 answers:
Alika [10]3 years ago
7 0
Hello there lol :))))
Yuri [45]3 years ago
3 0
I don’t see what you need help with but thanks:)
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A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O or pure K2O2. From this informa
Arte-miy333 [17]

Yes , the chemist can answer if the compound in K2O or K2O2

The chemical formula and composition of both the compounds is entirely different. The compound K2O2 has an additional molecule of oxygen than K2O and hence will have have higher molecular mass.

In the compound K2O

molecular mass= 2x 39+16 =94

mass ratio of K in compound= 78/94 = 0.830

In the compound K2O2

molecular mass= 2x 39+16X2 =110

mass ratio of K in compound= 78/110 = 0.710

and hence by the required ratio while extracting K , the chemist may know if the compound is K20 or K2O2

If the ratio is anything different from 0.830 and 0.710 then the compund will be something different

#SPJ9

5 0
2 years ago
11. Which of the following best explains why CO2 gas is easily compressible but solid
Oduvanchick [21]

Answer:

The right answer is C. The molecules of solid CO2 are much closer together than the molecules of CO2 gas.

8 0
4 years ago
A company sells a natural medicine with plant ingredients to help treat dementia, a disease in which people have a hard time rem
sammy [17]
I think it is the second one. hope it helps! :)
5 0
4 years ago
Read 2 more answers
Someone help me please!!!
Montano1993 [528]

A. 6 moles

B. 9 moles

C. 3 moles

D.  20 moles

I think please check me, in case I am wrong

8 0
3 years ago
Calculate the freezing point of a solution containing 15 grams of kcl and 1650.0 grams of water. the molal-freezing-point-depres
Soloha48 [4]
Answer is: freezing point is -0,226°C.
Answer is: the molal concentration of glucose in this solution is 1,478 m.
m(KCl) = 15 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 15 g ÷ 74,55 g/mol.
n(KCl) = 0,2 mol
m(H₂O) = 1650 g ÷ 1000 g/kg = 1,65 kg.
b = n(KCl) ÷ m(H₂O).
b = 0,2 mol ÷ 1,65 kg = 0,122 m.
Kf(water) = 1,86°C/m.
ΔT = Kf(water) · b(solution).
ΔT = 1,86°C/m · 0,122 m.
ΔT = 0,226°C.
4 0
3 years ago
Read 2 more answers
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