I WILL MARK BRAINLIEST PLZ HELP ASAP, thanks :)

Anit [1.1K]

Answer:

Research is constantly deepening our understanding of chemistry, and leading to new discoveries. Chemistry will help us solve many future problems, including sustainable energy and food production, managing our environment, providing safe drinking water and promoting human and environmental health.Chemistry is a big part of your everyday life. You find chemistry in daily life in foods you eat, air you breathe, soap, your emotions and literally every object you can see or touch. ... Food is made from chemicals. Many of the changes you observe in the world around you are caused by chemical reactions.By observing chemical reactions, we are able to understand and explain how the natural world works. Chemical reactions turn food into fuel for your body, make fireworks explode, cause food to change when it is cooked, make soap remove grime, and much more.

6 0

3 years ago

The protein lysozyme unfolds at a transition temperature of 75.5°C, and the standard enthalpy of transition is 509 kJ mol-1. Cal

spin [16.1K]

Answer:

0.4774 KJ/K.mol

Explanation:

We are told that the transition at 25.0°C occurs in three steps. Steps i, ii and iii.

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii

Now,

C_p,m(unfolded protein) = C_p,m(folded protein) + 6.28 kJ/K.mol

Now, for the first process, ΔS_i is given as;

ΔS_i = C_p,m × In(T2/T1)

We are given;

T1 = 25°C = 25 + 273.15K = 298.15 K

T2 = 75.5°C = 75.5 + 273.15 K=348.65 K

Thus;

ΔS_i = C_p,m × In(348.65/298.15)

Now, for the third process, ΔS_iii is given as;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(T1/T2)

Thus;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)

Now, we don't know C_pm. So, we have to find a way to eliminate it. We will do it by rewriting In(298.15/348.65) in such a way that when ΔS_iii is added to ΔS_i, C_p,m will cancel out. Thus;

In(298.15/348.65) can also be written as;

In(348.65/298.15)^(-1) or

- In(348.65/298.15)

Thus;

ΔS_iii = - [(C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)]

Now, let's add ΔS_iii to ΔS_i to get;

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] + [(-C_p,m - 6.28 kJ/K.mol) × In(348.65/298.15)]

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] - [C_p,m × In(348.65/298.15)] - [6.28In(348.65/298.15)]

First 2 terms will cancel out to give;

ΔS_i + ΔS_iii = -6.28In(348.65/298.15)

ΔS_i + ΔS_iii = -0.9826 KJ/K.mol

Now,for process ii;

ΔS_ii = standard enthalpy of transition/Transition Temperature

Thus;

ΔS_ii = (509 KJ/K.mol)/348.65

ΔS_ii = 1.46 KJ/K.mol

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii = -0.9826 + 1.46 = 0.4774 KJ/K.mol

5 0

3 years ago

a 25.5 liter balloon holding 3.5 moles of carbon dioxide leaks. If we are able to determine that 1.9 moles of carbon dioxide esc

kap26 [50]

Answer:

11.66 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If P and T are constant, and have different values of n and V:

(V₁n₂) = (V₂n₁).

V₁ = 25.5 L, n₁ = 3.5 mol.

V₂ = ??? L, n₂ = 3.5 mol - 1.9 mol = 1.6 mol.

∴ V₂ = (V₁n₂)/(n₁) = (25.5 L)(1.6 mol)/(3.5 mol) = 11.66 L.

4 0

3 years ago

Read 2 more answers

How many moles of carbon dioxide gas can be produced when 7.94 moles of benzene (C6H6) react with excess oxygen? Be sure to show

Sliva [168]

The balanced equation is

2 C6H6 +15 O2 = 12 CO2 + 6 H2O 

the ratio between C6H6 and CO2 is 2 : 12 

moles CO2 produced = 7.94 x 12 / 2 =47.6

6 0

3 years ago

If uranium-235 is bombarded with a neutron, it will temporarily become

stealth61 [152]

All atoms consist of a nucleus with protons and neutrons that is surrounded by a sea of electrons. If Uranium-235 is bombarded with a neutron then the atom's atomic number will remain the same but its mass will increase by 1 unit. Thus, it will temporarily become Uranium-236.

6 0

2 years ago