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snow_tiger [21]
3 years ago
13

Match the image with the correct invention

Chemistry
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

1. Watt stream engine

2. McCormick reaper

3. Fulton steamboat

These are the correct answers.

Have A good day!!  :)

xxTIMURxx [149]3 years ago
6 0

Answer:

I hope this helps, have a nice day! ❤

Explanation:

1. Watt steam engine

2. McCormick reaper

3. Fulton steamboat

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Nuclear energy can come from
s344n2d4d5 [400]
D. all of these can produce nuclear energy
5 0
3 years ago
Type the correct answer in the box. Express your answer to three significant figures. This balanced equation shows the reaction
Ratling [72]

Answer:

514.5 g.

Explanation:

  • The balanced equation of the reaction is: 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O.
  • It is clear that every 2.0 moles of NaOH react with 1.0 mole of H₂SO₄ to produce 1.0 mole of Na₂SO₄ and 2.0 moles of 2H₂O.
  • Since NaOH is in excess, so H₂SO₄  is the limiting reactant.
  • We need to calculate the no. of moles of 355.0 g of H₂SO₄:

n of H₂SO₄ = mass/molar mass = (355.0 g)/(98.0 g/mol) = 3.622 mol.

Using cross multiplication:

∵ 1.0 mol H₂SO₄ produces → 1.0 mol of Na₂SO₄.

∴ 3.622 mol H₂SO₄ produces → 3.662 mol of Na₂SO₄.

  • Now, we can get the theoretical mass of Na₂SO₄:

∴ mass of Na₂SO₄ =  no. of moles x molar mass = (3.662 mol)(142.04 g/mol) = 514.5 g.

8 0
2 years ago
Which of the following best describes how forces affect matter?
OlgaM077 [116]

Answer:

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3 0
3 years ago
The equilibrium constant for the gas-phase isomerization of borneol (c10h17oh) to isoborneol at 503 k is 0.106. a mixture consis
Dimas [21]
The solution is as follows:

K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106

The molar mass of isoborneol/borneol is 154.25 g/mol

Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol

Use the ICE approach

        borneol  →  isoborneol
I         0.0972           0.0486
C         -x                     +x
E     0.0972 - x        0.0486 + x

Total moles = 0.1458

Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P

0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832 

Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
6 0
3 years ago
The pH of an acid has nothing to do with the strength of the acid.
Levart [38]

Answer:

false

Explanation:

6 0
3 years ago
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