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2 years ago

Match the image with the correct invention

Chemistry

2 answers:

PolarNik [594]2 years ago

8 0

Answer:

1. Watt stream engine

2. McCormick reaper

3. Fulton steamboat

These are the correct answers.

Have A good day!! :)

xxTIMURxx [149]2 years ago

6 0

Answer:

I hope this helps, have a nice day! ❤

Explanation:

1. Watt steam engine

2. McCormick reaper

3. Fulton steamboat

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What is the concentration of silver ions where silver iodide, Agl, is in a solution of hydroiodic

jonny [76]

Answer:

$[Ag^+]=2.82x10^{-4}M$

Explanation:

Hello there!

In this case, for the ionization of silver iodide we have:

$AgI(s)\rightleftharpoons Ag^+(aq)+I^-(aq)\\\\Ksp=[Ag^+][I^-]$

Now, since we have the effect of iodide ions from the HI, it is possible to compute that concentration as that of the hydrogen ions equals that of the iodide ones:

$[I^-]=[H^+]=10^{-3.55}=2.82x10^{-4}M$

Now, we can set up the equilibrium expression as shown below:

$Ksp=8.51x10^{-17}=(x)(x+2.82x10^{-4})$

Thus, by solving for x which stands for the concentration of both silver and iodide ions at equilibrium, we have:

$x=[Ag^+]=2.82x10^{-4}M$

Best regards!

6 0

2 years ago

When 1.045 g of CaO is added to 50.0 mL of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C.

Rus_ich [418]

Answer:

1.71 kJ/mol

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

$\Delta H=m\times C\times \Delta T$

Where,

$\Delta H$ is the enthalpy change

m is the mass

C is the specific heat capacity

$\Delta T$ is the temperature change

Thus, given that:-

Mass of CaO = 1.045 g

Specific heat = 4.18 J/g°C

$\Delta T=32.3-25.0\ ^0C=7.3\ ^0C$

So,

$\Delta H=1.045\times 4.18\times 7.3\ J=31.88713\ J$

Also, 1 J = 0.001 kJ

So,

$\Delta H=0.03189\ kJ$

Also, Molar mass of CaO = 56.0774 g/mol

$Moles=\frac{Mass}{Molar\ mass}=\frac{1.045}{56.0774}\ mol=0.01863\ mol$

Thus, Enthalpy change in kJ/mol is:-

$\Delta H=\frac{0.03189}{0.01863}\ kJ/mol=1.71\ kJ/mol$

8 0

2 years ago

How much heat does a 100. g sample of copper absorb when its temperature increases by 30.0°C? The specific heat of copper is 0.3

erica [24]

Answer:

$\boxed {\boxed {\sf B. \ 1170 \ Joules }}$

Explanation:

We are asked to find how much heat a sample of copper absorbs when the temperature is increased.

Since we know the mass, temperature increase, and specific heat capacity, we can use the following formula to calculate heat.

$q= mc \Delta T$

The mass of the copper sample is 100 grams, the temperature is changed or increased by 30.0 degrees Celsius, and the specific heat of copper is 0.39 Joules per gram degrees Celsius.