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sashaice [31]
4 years ago
12

Polar substances will usually dissolve in _____.

Chemistry
2 answers:
Savatey [412]4 years ago
7 0
Hello!

When we want to dissolve something, we need a solvent in order to do it. So if we have a polar substance, we will need a polar solvent in order to dissolve it. 

<span>Polar substances will usually dissolve in polar solvents.

You can feel free to let me know if you have any questions regarding this!
Thanks!

- TetraFish</span>
leva [86]4 years ago
5 0
Polar solvents  
hope it helps
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Indicate whether each of the following statements about the heme-binding site in myoglobin is true or false. If you think a stat
Likurg_2 [28]

Answer:

A. True

B. False

C. False

D. True

E. False

Explanation:

A. The proximal histidine covalently binds iron.

This statement is true because the proximal histidine is covalently bonded to the fifth coordination position of iron in myoglobin

B. The distal histidine covalently binds oxygen.

This statement is false because the distal histidine interacts with the oxygen covalently bonded to the sixty coordination position of iron by means of a hydrogen bond not a covalent bond.

C. The distal histidine binds iron

This statement is false because the distal histidine is not bonded to iron but to oxygen but stabilizes the oxygen bonded to iron

D. Free heme binds CO with the Fe, C and O atoms in a linear array.

This statement is true because free heme has more affinity for CO than O2 as it has the least steric hindrance when the Fe, C, and O atoms lie in a straight line. On the other hand, when O2 binds to free heme, the axis of the oxygen molecule is positioned at an angle to the Fe-O bond thereby producing significant steric hindrance.

E. The iron in heme binds the oxygen atom of CO.

This statement is false because the iron in heme binds to the carbon atom, C, of CO rather than to oxygen atom.

7 0
3 years ago
When aluminum, AlAl, metal is dipped in an aqueous solution of hydrochloric acid, HClHCl, hydrogen gas, H2H2, is produced with t
kifflom [539]

Answer:

Balanced equation: 2Al(s)+6HCl(aq.)\rightarrow 2AlCl_{3}(aq.)+3H_{2}(g)

Explanation:

  • Al is an metallic species with a standard reduction potential of -1.66 V( E_{Al^{3+}\mid Al}^{0}=-1.66V).
  • H_{2} is present at the intermediate position in electrochemical series with a standard reduction potential of 0 V (E_{H^{+}\mid H_{2}}^{0}=0V).
  • So, when Al is dipped in aqueous solution of HCl, Al is readily oxidized to produce Al^{3+} whereas H^{+} is reduced to H_{2} .
  • Hence, as a whole, aqueous AlCl_{3} and gaseous H_{2} is produced as products.

Balanced equation: 2Al(s)+6HCl(aq.)\rightarrow 2AlCl_{3}(aq.)+3H_{2}(g)

5 0
4 years ago
What amount of heat energy is required to raise the temperature of 152 g of water from 24 °C to 74 °C.
DIA [1.3K]

Answer:

Q = 31798.4J = 31.79kJ

Explanation:

Heat energy (Q) = ?

Mass (m) = 152g

T1 = 24°C

T2 = 74°C

Specific heat capacity of water (c) = 4.184J/g°C

Q = Mc∇T

Q = 152 * 4.184 * (74 - 24)

Q = 635.968 * 50

Q = 31798.4J

Q = 31.79kJ

Heat required is 31.79kJ

6 0
3 years ago
What mass of sulfur has to burn to produce 4.5L SO2 at 300°C and 101 kPa in the following reaction?s(s)+O2(g) SO,(g)
Alex_Xolod [135]
<span>Answer: option B. 3.07 g

Explanation:

1) given reaction:

S(s) + O₂ (g) → SO(g)

2) Balanced chemical equation:

</span><span>2S(s) + O₂ (g) → 2SO(g)

3) Theoretical mole ratios:

2 mol S : 1 mol O₂ : 2 mol SO

3) number of moles of 4.5 liter SO₂ at</span><span> 300°C and 101 kPa

use the ideal gas equation:

pV = nRT

with V = 4.5 liter
p = 101 kPa
T = 300 + 273.15 K = 573.15 K
R = 8.314 liter×kPa / (mol×K)

=> n = pV / (RT) =

n =  [101 kPa × 4.5 liter] / [8.314 (liter×kPa) / (mol×K)  × 573.15 K ]

n = 0.0954 mol SO

4) proportion with the theoretical ratio S / SO

 2 mol S                   x
-------------- = ----------------------
 2 mol SO      0.0954 mol SO

=> x = 0.0954 mol S.

5) Convert mol of S to grams by using atomic mass of S = 32.065 g/mol

mass = number of moles × atomic mass

mass = 0.0954 mol × 32.065 g/mol = 3.059 g of S

6) Therefore the answer is the option B. 3.07 g
</span>
8 0
4 years ago
Give one hazard of using sodium hydroxide and state how to reduce the risks from this hazard.
Roman55 [17]

Answer:

Sodium hydroxide is <u>very corrosive</u>. It can cause irritation to the eyes, skin, and mucous membrane; an allergic reaction; eye and skin burns; and temporary loss of hair. Workers may be harmed from exposure to sodium hydroxide.

Explanation:

<u>How to reduce:</u>

Inhalation: Move victim to fresh air.

Skin Contact: Avoid direct contact

Eye Contact: Avoid direct contact

Ingestion: Have victim rinse mouth with water.

5 0
3 years ago
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