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shtirl [24]
3 years ago
14

A syrup added to an empty container with a mass of 115.25g . When 0.100 pint of syrup is added, the total mass of the container

and syrup is 182.48g. Determine the density ...?
Physics
1 answer:
sesenic [268]3 years ago
3 0
<span>Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance. We calculate as follows:

Density = 182.48 g - 115.25 g / 0.100 pint ( 0.47 L / 1 pint ) = 67.23 g/0.047L
Density =1430.43 g/L </span>
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An object that has kinetic energy must what ?
11Alexandr11 [23.1K]

An object that has kinetic energy must be <em>moving</em>.

The formula for an object's kinetic energy is

KE = (1/2) · (the object's mass) · <u><em>(the object's speed)²</em></u>

As you can see from the formula, if the object has no speed, then its kinetic energy is zero.  That's why kinetic energy is usually called the "energy of motion", and if an object HAS kinetic energy, then that tells you right away that it must be moving.

4 0
4 years ago
Help me I do not understand
ololo11 [35]

Answer:

170N

Explanation:

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4 0
3 years ago
Please help on this one!!
inysia [295]

The energy transformations that occur as you coast down long hill on a bicycle, including the brakes to make the bike stop at the bottom, is that at the top of the hill you have high GPE AND LOW KE, on your way down you have HIGH KE AND LOW GPE, and at the bottom you have thermal energy due to the stop of the brakes.

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3 0
3 years ago
Two circles are drawn in a 12-inch by 14-inch rectangle. Each circle has a diameter of 6 inches. If the circles do not extend be
Dennis_Churaev [7]

Answer:

d = 10 inch

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So if, one side is 12 inch, and the other is 14 inch, we can use the Pitagoras theorem which is:

d = √(a²) + (b)²

Where a and b, are the lenght of the rectangle, but without the lenght  of the diameter of both circles.

With this, the expression is this:

d = √(14 - 6)² + (12 - 6)²

d = √64+36

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6 0
3 years ago
A block of mass 14.9 kg is pulled to the right by an applied force of 39.4 N. If it moves with constant velocity, how much frict
lakkis [162]

The frictional force is 39.4 N

Explanation:

We can solve this problem by applying Newton's 2nd law of motion: in fact, the net force acting on the block is equal to the product between its mass and its acceleration. So we can write

\sum F = ma

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\sum F is the net force

m is the mass

a is the acceleration

Here we know that the box is moving with constant velocity, so its acceleration is zero:

a=0

This means that the net force is also zero:

\sum F=0

The net force on the block is given by the applied force, forward, and the frictional force, backward:

\sum F = F_a-F_f=0

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Therefore, solving for F_f,

F_f=F_a=39.4 N

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

8 0
3 years ago
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