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1 answer:
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Answer:
The shortest possible stopping distance of the car is 175.319 meters.
Explanation:
In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:
(Eq. 1)
(Eq. 2)
After quick handling, we get that deceleration experimented by the car is equal to:
(Eq. 3)
Where:
- Deceleration of the car, measured in meters per square second.
- Kinetic coefficient of friction, dimensionless.
- Gravitational acceleration, measured in meters per square second.
If we know that and
, then deceleration of the car is:
The stopping distance of the car (), measured in meters, is determined from the following kinematic expression:
(Eq. 4)
Where:
- Initial speed of the car, measured in meters per second.
- Final speed of the car, measured in meters per second.
If we know that ,
and
, stopping distance of the car is:
The shortest possible stopping distance of the car is 175.319 meters.
Answer:
<h2>a) 50°</h2><h2>b) 40°</h2>Explanation:
Check the complete diagram n the attachment below
a) The angle of incidence on a plane surface is the angle between the incidence ray and the normal ray acting on a plane surface. The normal ray is the ray perpendicular to the surface while the incidence ray is the ray striking a plane surface.
According to the diagram, the angle of reflection r₂ on M₂ is 90°-g where g is the angle of glance.
Given angle of glance on M₂ to be 40°, r₂ = 90-40 = 50°
According the second law of reflection, the angle of incidence = angle of reflection, therefore i₂ = r₂ = 50° (on M₂)
Also ∠OO₂O₁ = ∠OO₁O₂ = 40° (angle of glance on M₁){alternate angle}
The angle of incidence on M₁ = 90° - 40° = 50°
b) The angle of incidence to the surface of M₁(∠PO₁A)will be the angle of glance on M₁ which is equivalent to 40°
