Ask question

Ask question

All categories

2 years ago

13

You can determine the index of refraction of a substance by determining its critical angle. (a) What is the index of refraction

of a substance that has a critical angle of 47.3Â° when submerged in ethanol, which has an index of refraction of 1.361? (b) What would the critical angle be for this substance in air?

1 answer:

gregori [183]2 years ago

3 0

Answer:

a )1.851

b ) 32.68°

Explanation:

The relation between critical angle and index of refraction is as follows

Sin C = 1 / μ

C is critical angle and μ is refractive index.

Given C = 47.3

Sin 47.3 = 1 / μ

0.735 = 1 / μ

μ = 1 / .735

= 1.36

This is with respect to ethanol .

1.36 = refractive index of material / refractive index of ethanol

refractive index of material = 1.36 x refractive index of ethanol

= 1.36 x 1.361 = 1.851

If critical angle for this substance be A

Sin A = 1 / 1.851 = .54

A = 32.68° .

You might be interested in

Most energy obtained from water is converted from _____.

Snowcat [4.5K]

Potential energy behind dams

7 0

2 years ago

Read 2 more answers

A student investigated how the mass of water in an electric kettle affected the time taken for the water to reach boiling point.

Sedbober [7]

Answer:

1.because of the heat produced by the socat

2. they should have control how they placed the heater

3. because the water is to much

4.because is different from the question

5. because that is how the question is

4 0

2 years ago

You push on a cart (18.0kg) at a 30 degree below horizontal angle. The coefficient of kinetic friction between the chair and the

podryga [215]

Given that force is applied at an angle of 30 degree below the horizontal

So let say force applied if F

now its two components are given as

$F_x = Fcos30$

$F_y = Fsin30$

Now the normal force on the block is given as

$N = Fsin30 + mg$

$N = 0.5F + (18\times 9.8)$

$N = 0.5F + 176.4$

now the friction force on the cart is given as

$F_f = \mu N$

$F_f = 0.625(0.5F + 176.4)$

$F_f = 110.25 + 0.3125F$

now if cart moves with constant speed then net force on cart must be zero

so now we have

$F_f + F_x = 0$

$Fcos30 - (110.25 + 0.3125F) = 0$

$0.866F - 0.3125F = 110.25$

$F = 199.2 N$

so the force must be 199.2 N

8 0

2 years ago

Suppose you need your silicon circuit element to run continuously for 3 minutes before it shuts off long enough to cool back dow

Zigmanuir [339]

The maximum rate at which energy can be added to the circuit element mathematically given as

$MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}$

<h3>What is the maximum rate at which energy can be added to the circuit element?</h3>

Generally, the equation for P is mathematically given as

$P=\ln s \frac{\Delta T}{\Delta t}$

Therefore

$Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}$

$\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}$

$\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}$

Max temp Change

$MaxT=5.6^{\circ} \mathrm{C}$

$\text { time }=3 \times 60$

t=180s

In conclusion, Max Energy Rate

$MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}$

$MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}$

Read more about Energy

brainly.com/question/13439286

#SPJ1

3 0

1 year ago

To apply Problem-Solving Strategy 21.1 Faraday's law. A closely wound rectangular coil of 80 turns has dimensions 25.0 cm by 40.

Alisiya [41]

Answer:

58.37 V

Explanation:

Given that

Number of winding on coil, N = 80 turns

Area of the coil, A = 25 cm * 40 cm = 0.25 m * 0.4 m

Magnitude of magnetic force, B = 1.1 T

Time of rotation, t = 0.06 s

See the attachment for calculations

8 0

2 years ago

Read 2 more answers