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3 years ago

When chlorine gas is passed through a potassium bromide solution, bromine forms in a potassium chloride solution?

1 answer:

4 0

Yes because chlorine is more reactive than bromine, it displaces bromine in potassium bromide solution.
Forms bromide *gas* in KCl solution

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The ideal gas constant is..?

Mice21 [21]

Answer:

hope it is use full to you

Explanation:

The gas constant is denoted by the symbol R or R. It is equivalent to the Boltzmann constant, but expressed in units of energy per temperature increment per mole, i.e. the pressure–volume product, rather than energy per temperature increment per particle.

it is a physical constant that is featured in many fundamental equations in the physical sciences, such as the ideal gas law, the Arrhenius equation, and the Nernst equation. As a consequence, the value of the gas constant is also exactly defined.

5 0

3 years ago

You have a ball with a density of 1.3 g/mL and a mass of 8.5 g. what is the volume of the ball

RoseWind [281]

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass of ball = 8.5 g

density = 1.3 g/mL

It's volume is

$volume = \frac{8.5}{1.3} \\ = 6.538461...$

We have the final answer as

Hope this helps you

6 0

3 years ago

Suppose that you have a 60.0% solution of NaOH. How many milliliters of water must be added to 30.0 mL of this solution to prepa

defon

Answer:

<u>21.4 ml (second choice)</u>

Explanation:

a) C₁ = 60.0% (initial solution)

b) V₁ = 30.0 ml (initial solution)

c) C₂ = 0% (pure water)

d) V₂ = ? (pure water)

e) C₃ = 35.0% (final concentration)

<u>2) Formula:</u>

C₁V₁ + C₂V₂ = C₃V₃
V₁ + V₂ = V₃ (assuming volume addtivity)

<u>3) Solution:</u>

<u />

a) Substitute values in the first formula:

60.0% × 30 ml + 0 = 35% (30 ml + V₂)

b) Solve the equation (units are supressed just to manipulate the terms)

18 = 10.5 + 0.35V₂

0.35V₂ = 18 - 10.5 = 7.5

V₂ = 7.5 / 0.35 = 21.4 ml ← answer

3 0

4 years ago

When an atom of iron loses all of its 4s electrons and one of its 3d electrons, what is its charge?

icang [17]

There are two electrons in 4s and 6 in 3d. When you lose 3 electrons, you will be left with an ion of 3+ charge!

5 0

4 years ago

A 1.0 g sample of a cashew was burned in a calorimeter containing 1000. g of water, and the temperature of the water changed fro

Savatey [412]

Answer:

The correct answer is option C.

Explanation:

1.0 g sample of a cashew :

Heat released on combustion of 1.0 gram of cashew = -Q

We have mass of water = m = 1000 g

Specific heat of water = c = 4.184 J/g°C

ΔT = 30°C - 25°C = 5°C

Heat absorbed by the water : Q

$Q=1000 g\times 4.184 J/g^oC\times 5^oC=20,920 J$

Heat released on combustion of 1.0 gram of cashew is -20,920 J.

3.0 g sample of a marshmallows :

Heat released on combustion of 3.0 g sample of a marshmallows = -Q'

We have mass of water = m = 2000 g

Specific heat of water = c = 4.184 J/g°C

ΔT = 30°C - 25°C = 5°C

Heat absorbed by the water : Q'

$Q'=2000 g\times 4.184 J/g^oC\times 5^oC=41,840 J$

Heat released on 3.0 g sample of a marshmallows= -Q' = -41,840 J

Heat released on 1.0 g sample of a marshmallows : q

$q =\frac{-Q'}{3} = \frac{-41,840 J}{3}=-13,946.67 J$

Heat released on combustion of 1.0 gram of marshmallows -13,946.67 J.

-20,920 J. > -13,946.67 J

The combustion of 1.0 g of cashew releases more energy than the combustion of 1.0 g of marshmallow.

5 0

3 years ago