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3 years ago

4.05 kg + 567.95 g + 100.1 g add the correct value using the correct sig figs and or least precise degree of precision.

1 answer:

7 0

To get the least degree of precision I would model it after the kg amount or 4.05 or two decimal places so I would add 0.56795 or to two places would be 0.57 kg and then 0.1001 kg would be 0.1 kg so my answer would be 4.72 kg. In contrast, the greatest degree of precision would be 4050g + 567.95 grams plus 100.1 g= 4718.05 grams or 4.71805 kg. At least that is what I would think..

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when you draw a bow across a violin string which kind of wave is created in the air surrounding the string

Lilit [14]

Answer:

When the string on a violin vibrates, waves move in both directions along the string, interfering with each other. These waves are standing waves.

Explanation:

What are Standing Waves?

The Standing Waves are waves generated due to the vibrational frequency that produces reflected waves capable of interfering with the incident waves.

8 0

2 years ago

Consider the neutralization reaction 2 HNO 3 ( aq ) + Ba ( OH ) 2 ( aq ) ⟶ 2 H 2 O ( l ) + Ba ( NO 3 ) 2 ( aq ) A 0.120 L sample

k0ka [10]

Answer:

The concentration of the HNO3 solution is 0.150 M

Explanation:

Step 1: Data given

Volume of the unknown HNO3 sample = 0.120 L

Volume of the 0.200 M Ba(OH)2 = 45.1 mL

Step 2: The balanced equation

2HNO3 + Ba(OH)2 ⟶ Ba(NO3)2 + 2H2O

Step 3: Calculate moles Ba(OH)2

moles Ba(OH)2 = molarity * volume

moles Ba(OH)2 = 0.200 M * 0.0451 L

moles Ba(OH)2 = 0.00902 moles

Step 4: Calculate moles of HNO3

For 1 mole of Ba(OH)2 we need 2 moles of HNO3

For 0.00902 moles of Ba(OH)2 we need 2*0.00902 = 0.01804 moles

Step 5: Calculate molarity of HNO3

molarity = moles / volume

molarity = 0.01804 / 0.120 L

Molarity = 0.150 M HNO3

The concentration of the HNO3 solution is 0.150 M

6 0

4 years ago

The mass of an electron is about 9.11 × 10 -9 kg., write this whole number

Pepsi [2]

Answer:0.00000009

Explanation:

9.11 × （1/1000000000）=0.00000009

8 0

3 years ago

The volume of carbon gas at 5.0 ATM was measured to be 363 ml. What will the pressure be if the volume is change to .00020 ml?

aleksley [76]

Answer:

The answer to your question is P2 = 9075000 atm

Explanation:

Data

Pressure 1 = P1 = 5 atm

Volume 1 = V1 = 363 ml

Pressure 2 = P2 = ?

Volume 2 = 0.0002 ml

Process

To solve this problem use Boyle's law

P1V1 = P2V2

-Solve for P2

P2 = P1V1/V2

-Substitution

P2 = (5 x 363) / 0.0002

-Simplification

P2 = 1815 / 0.0002

-Result

P2 = 9075000 atm

5 0

4 years ago

Are you for or against transgender? why?

EleoNora [17]

Explanation:

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7 0

3 years ago

Read 2 more answers