KOH + HBr ---> KBr + H2O
0,3 moles of HBr ---in-------1000ml
x moles of HBr-------in------75ml
x = 0,0225 moles of HBr
according to the reaction: 1 mole of KOH = 1 mole of HBr
so
0,0225 moles of HBr = 0,0225 moles of KOH
0,0225 mole of KOH------in-----45ml
x moles of KOH -----------in------1000ml
x = 0,5 moles of KOH
answer: 0,5 mol/dm³ KOH (molarity)
The molecular mass of sucrose is 342.3<span> grams per mole (g/mol).</span>
When 2 molecules of pyruvate from glycolysis enters the mitochondria,
2 molecules of CO2 are released
The answer is B. Precipitation