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SVETLANKA909090 [29]
2 years ago
15

when you draw a bow across a violin string which kind of wave is created in the air surrounding the string

Chemistry
1 answer:
Lilit [14]2 years ago
8 0

Answer:

When the string on a violin vibrates, waves move in both directions along the string, interfering with each other. These waves are standing waves.

Explanation:

What are Standing Waves?

The Standing Waves are waves generated due to the vibrational frequency that produces reflected waves capable of interfering with the incident waves. 

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In the balanced chemical reaction shown below, what is the molar ratio of O2 to H2O
icang [17]

Answer: 5:3

Explanation:

4 0
3 years ago
a) What substances are present in an aqueous buffer composed of HC2H3O2 and C2H3O2 - ?b) What happens when LiOH is added to a bu
Alex17521 [72]

Answer:

a) HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻

b) HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

Explanation:

a) In a HC₂H₃O₂/C₂H₃O₂⁻ buffer system, the following reactions take place:

HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺

C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻

Thus, the species present are: HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻.

b) When LiOH is added to the buffer system, it is partially neutralized according to the following equation.

HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) When HBr is added to the buffer system, it is partially neutralized according to the following equation.

C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

3 0
3 years ago
Diana raises a 1000. N piano a distance of 5.00 m using a set of pulleys. She pulls
Alina [70]

Answer:

a) 250 N

b) 50 N

c) 5000 J

d) 4

e) 3.33

Explanation:

Given that weight of piano (F_r) = 1000 N, distance moved by pulley (d_r) = 5 m and the rope used (d_e) =20 m

a) The effort applied (F_e) if it was an ideal machine is:

F_e=\frac{F_rd_r}{d_e} = \frac{1000*5}{20}=250N

b) If the actual effort  = 300 N

The force to overcome friction = actual effort - F_e = 300 - 250 = 50 N

c) Work output = F_rd_r=1000*5=5000J

d) ideal mechanical  advantage (IMA) = \frac{d_e}{d_r} =\frac{20}{5} = 4

e) Input force = 300 N, Therefore:

actual mechanical advantage = F_r / input force = 1000 / 300 = 3.33

5 0
4 years ago
How many atoms are there in 5.7 mol of hafnium?
Mashutka [201]
<span>In 5.70 mol of Hafnium there are 34,326 208 203*10^23 atoms.</span>
7 0
4 years ago
Read 2 more answers
To what Celsius temperature must 67.0 mL of krypton gas at 18.0°C be changed so the volume will triple? Assume the pressure and
Mice21 [21]

Answer: 600°C

Explanation:

This reaction is explained by Charles' law as the pressure is constant.

From the question, we obtained:

V1 = 67mL

T1 = 18°C = 18 +273 = 291K

V2 = 3V1 ( Vol is tripled) = 3x67 = 201mL

T2 =?

Applying the Charles' law,

V1 /T1 = V2 /T2

67/291 = 201 / T2

Cross multiply to express in linear form.

67xT2 = 291x201

Divide both side by 67, we have:

T2 = (291x201) /67

T2 = 873K

Converting to Celsius temperature, we have

T°C = K — 273

T°C = 873 — 273 = 600°C

8 0
3 years ago
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