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3 years ago

Are you for or against transgender? why?

Chemistry

2 answers:

Oksanka [162]3 years ago

8 0

Answer:

all for it 8) !! i have several friends that are trans in fact.

Explanation:

ppl that don't support trans peeps are going to get punted into the sun with no mercy

im nonbinary, but also identify as trans too (the white stripe on the transgender flag is actually "for those who are transitioning or consider themselves having a neutral or undefined gender," according to Monica Helms, who made the most commonly seen trans flag. :] they don't all identify as trans but can if they want to.

also, a common misconception is that all nonbinary people have to/use they/them pronouns, which is not true. they can use whatever they want because pronouns do not equal gender in most cases. also because they don't have to be put into a strict box of what you can and can't use.

EleoNora [17]3 years ago

7 0

Explanation:

that u know right .........................

You might be interested in

for a neutralization reaction, would you expect the magnitude of q to increase, decrease, or stay the same if the concentration

ikadub [295]

For a neutralization reaction, the value of q(heat of neutralization) is doubled when the concentration of only the acid is doubled.

A neutralization reaction is a reaction in which an acid reacts with a base to yield salt and water. Ionically, a neutralization reaction goes as follows; H^+(aq) + OH^-(aq) ------> H20(l).

The heat of neutralization (Q) of the system depends on the concentration of the solutions. Since Q is dependent on concentration, if the concentration of any of the reactants is doubled, more heat is evolved hence Q is doubled.

Learn more: brainly.com/question/10323185

4 0

2 years ago

Please help :) ill mark you as the brainiest hope you have a good day

Hitman42 [59]

Have a wonderful day :) thanks for the points

5 0

3 years ago

What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?

yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃ + 3C → 4Fe + 3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5 . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83 . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

5 0

3 years ago

If 2,035 cal of heat is added to a 500.0 g sample of water at 35.0°C, what is the final

Lynna [10]

Answer:

39.1 °C

Explanation:

Recall the equation for specific heat:

$q=mc \Delta T\\$

Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.

You should know that the specific heat of water is 1 cal/g/C.

Using the information in the question:

$2035=500(1)(T-35)\\2035=500T-17500\\500T=19535\\T=39.07$

The final temperature is about 39.1 °C.

5 0

3 years ago

If the initial temperature of a movable cylinder was 50 degrees Celsius

slega [8]

Answer:

8.45 L

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 50 °C

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 0 °C

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 50 °C

Initial temperature (T₁) = 50 °C + 273

Initial temperature (T₁) = 323 K

Final temperature (T₂) = 0 °C

Final temperature (T₂) = 0 °C + 273

Final temperature (T₂) = 273 K

Finally, we shall determine the new volume. This can be obtained as follow:

Initial temperature (T₁) = 323 K

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 273 k

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

2 × 5 / 323 = 1 × V₂ / 273

10 / 323 = V₂ / 273

Cross multiply

323 × V₂ = 10 × 273

323 × V₂ = 2730

Divide both side by 323

V₂ = 2730 / 323

V₂ = 8.45 L

Thus, the new volume is 8.45 L

5 0

3 years ago