Answer:
Explanation:
Initially no of atoms of A = N₀(A)
Initially no of atoms of B = N₀(B)
5 X N₀(A) = N₀(B)
N = N₀ 
N is no of atoms after time t , λ is decay constant and t is time .
For A
N(A) = N(A)₀ 
For B
N(B) = N(B)₀ 
N(A) = N(B) , for t = 2 h
N(A)₀ = N(B)₀
N(A)₀ = 5 x N₀(A)
= 5
= 5 
half life = .693 / λ
For A
.77 = .693 / λ₁
λ₁ = .9 h⁻¹
= 5
Putting t = 2 h , λ₁ = .9 h⁻¹
= 5 
= 30.25
2 x λ₂ = 3.41
λ₂ = 1.7047
Half life of B = .693 / 1.7047
= .4065 hours .
= .41 hours .
Answer:
A drop of water falling from a faucet into a sink
Answer:
The distance between the two slits is 1.2mm.
Explanation:
The physicist Thomas Young establishes, through its double slit experiment, a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.
(1)
Where 
is the distance between two adjacent maxima, L is the distance of the screen from the slits, 
is the wavelength and d is the separation between the slits.
If light pass through two slits a diffraction pattern in a screen will be gotten, at which each bright region corresponds to a crest, a dark region to a trough, as consequence of constructive interference and destructive interference in different points of its propagation to the screen.
Therefore, d can be isolated from equation 1.
(2)
Notice that it is necessary to express L and in units of millimeters.
⇒ 
⇒ 
Hence, the distance between the two slits is 1.2mm.
The answer to this is electric force. Hope it helps
Answer: The question has some details missing. Here is the complete question ; An molecule adsorbed at one site on a surface. An oxygen molecule is adsorbed onto a small patch of the surface of a catalyst. It's known that the molecule is adsorbed on 1 of 576 possible sites for adsorption (see sketch at right). Calculate the entropy of this system. Round your answer to 3 significant digits.
Explanation:
The stefan boltzmaan constant for entropy is given by ;
- we are given that 576 total possible sites in which O2 can get absorbed
- w = 576, k = 1.38 x 10-23J/k
plugging the values into the equation ;
S = 1.38 x 10-23J/k X In(576)
Entropy of the system = 8.79 X 10-23J/k
