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2 years ago

Please help me with question 2 !!!!

Chemistry

1 answer:

Fiesta28 [93]2 years ago

4 0

<h3>Answer :</h3><h3 />

a. NaF

b. MgO

c. Li2O

d. MgCl2

e. BeS

Do give it a brainliest if it helps you :)))

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How do I "predict the colour change that would be observed if carbon dioxide gas were bubbled into a mixture of calcium oxide, b

Effectus [21]

Hey there!

Just say what color you think the mixture would look like if those elements were combined. Personally I don't know because I don't have context, but if it comes to it just pick a color :)

Good luck, have a good night.

7 0

3 years ago

Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta

shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]$

Putting the values we get :

$\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]$

$\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]$

$\Delta H=-5314.8kJ$

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = $\frac{5314.8}{2}\times 1=2657.4kJ$

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0

3 years ago

If the following elements were to combine with each other, choose which demonstrate the Law of Multiple Proportion. Select all t

Ilia_Sergeevich [38]

Missing question: Z:X = 7:1 A:Z = 2.5:1 A:Z = 2.2:1 Y:X = 11:1.

Answer is:<span> Z:X = 7:1 and Y:X = 11:1.
Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.
In this example ratios are whole numbers, A:Z = 2.5 : 1 and A:Z = 2.2 : 1 are not whole number ratios.</span>

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2 years ago

What three types of Protists have been discovered

frosja888 [35]

Answer:

the answer is D

Explanation:

but hope this helps

8 0

2 years ago

Read 2 more answers

specify whether each of the items listed is hydrophilic or hydrophobic by dragging the labels into the appropriate box.

erik [133]

Hydrophilic;

Polar compounds

water

ions

glucose

Hydrophobic;

Triglycerides

cholesterol

Lipids

Oil

Carbohydrates

<h3>What are hydrophilic substances?</h3>

The term hydrophilic substances is used to describe the substances that could dissolve in water. They are those substances that are water soluble. Somehow, the substances must be polar because in chemistry like dissolves like.

The hydrophobic substances are those substances that do not dissolve in water. They are nonpolar and interact with other nonpolar substances.

The classification of the substances took place below;

Hydrophilic;

Polar compounds

water

ions

glucose

Hydrophobic;

Triglycerides

cholesterol

Lipids

Oil

Carbohydrates

Learn more about hydrophilic substances:brainly.com/question/4692308

#SPJ1

4 0

1 year ago