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Sever21 [200]
3 years ago
6

The radioisotope that has the longest half-life is the best to use in powering planet and space exploration vehicles because the

y can travel farther. Which radioisotope is the best to use?

Chemistry
2 answers:
adoni [48]3 years ago
8 0

Answer:

D. plutonium-239

Explanation:

BaLLatris [955]3 years ago
4 0

Answer : The radioisotope which has longest half-life and can be best to be used in powering planet and space exploration vehicle and travel farther will be Plutonium - 239 as it has the half life of 24065 years. Which in comparison to other radioisotopes is longest.


Hence, Plutonium - 239 can be the best suitable radioisotope for powering the planet and space exploration vehicle to travel farther.

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What is the mass of a neutron?<br><br> 1/2,000 amu<br> 1 amu<br> 2,000 amu<br> 1/200 amu
pashok25 [27]

Vas happenin!!



1 amu is the correct answer


Hope this helps


-Zayn Malik
8 0
3 years ago
Read 2 more answers
Determine whether you can swim in 1.00 x 10^27 molecules of water.​
zloy xaker [14]

Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, N_A, gives the number of molecules in one mole of a substance

N_A ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ N_A

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

7 0
3 years ago
What mass of natural gas (ch4) must you burn to emit 272 kj of heat?
balandron [24]
CH4 + 2 O2 ---> CO2 + 2 H2O Q = 891,6 kJ / mol CH4

1 mol CH4 = 16 g

16 g ---- 891,6 kJ
x g ----- 272 kJ

x = 272 kJ × 16 g / 891,6 kJ = 4,88 g

You must burn 4,88 g of CH4.

:-) ;-)
7 0
3 years ago
Tris {(hoch2)3cnh2} is one of the most common buffers used in biochemistry. a solution is prepared by adding enough tris and 12
shusha [124]

Given that,

The concentration of TRIS = 0.30 M

The concentration of TRIS+ = 0.60 M

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Now, by using the Hendersonn equation,

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7 0
3 years ago
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The relationships among which variable quantities are expressed by the ideal gas law equation?
Eva8 [605]

<u><em>The  variable quantities are expressed by the ideal gas law equation are; </em></u>

<u><em>pressure, volume, temperature, number of moles</em></u>

<u><em /></u>

This question is simply based on defining the ideal gas law.

  • Now, A gas is considered to ideal if its particles are so far from each other in such a manner that they don't exhibit any forces of attraction between themselves. Now, in real life this is not possible but under high temperatures and pressure, we can have something close to it and that's why ideal gas laws are very important.

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PV = nRT

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P is pressure

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n is number of moles

T is temperature

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The  variable quantities are expressed by the ideal gas law equation are;

<em>pressure, volume, temperature, number of moles</em>

Read more at; brainly.in/question/5212853

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3 years ago
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