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Sever21 [200]
3 years ago
6

The radioisotope that has the longest half-life is the best to use in powering planet and space exploration vehicles because the

y can travel farther. Which radioisotope is the best to use?

Chemistry
2 answers:
adoni [48]3 years ago
8 0

Answer:

D. plutonium-239

Explanation:

BaLLatris [955]3 years ago
4 0

Answer : The radioisotope which has longest half-life and can be best to be used in powering planet and space exploration vehicle and travel farther will be Plutonium - 239 as it has the half life of 24065 years. Which in comparison to other radioisotopes is longest.


Hence, Plutonium - 239 can be the best suitable radioisotope for powering the planet and space exploration vehicle to travel farther.

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Which of the following are examples of electromagnetic waves?
liubo4ka [24]

Answer:

C

Explanation:

Electromagnetic waves travel at the speed of light and do not require molecules (gas, solid or liquid) to vibrate and travel.

Soundwaves when singing or from thunder vibrate particles to reach our ears and are known as mechanical waves.

8 0
3 years ago
Please help
docker41 [41]
i gotchuuu i’m checking my answer now
7 0
3 years ago
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
3 years ago
Explain why a solution that is 1.3 M HF and 1.3 mM KF is not a good buffer. HF is a strong acid and cannot be used in a buffer s
zavuch27 [327]

Answer:

The ratio of acid to conjugate base is outside the buffer range of 10:1.

Explanation:

The Henderson-Hasselbalch equation for a buffer is

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}

A buffer should have

\dfrac{1}{10} \leq \dfrac{\text{[A$^{-}]$}}{\text{[HA]}} \leq \dfrac{10}{1}

For a solution that is 1.3 mol·L⁻¹ in HF and 1.3 mmol·L⁻¹ in KF, the ratio is

\dfrac{1.3 \times 10^{-3} }{1.3} = \dfrac{1}{1000}

The ratio of acid to conjugate base is 1000:1, which is outside the range of 10:1.

A is wrong. NF is a weak acid.

C is wrong. The two species are a conjugate acid-base pair.

D is wrong. Salts of Group 1 metals are soluble.

4 0
3 years ago
Which elements have the greatest tendency to behave as oxidizing agents?
son4ous [18]
The force acting between two charged particles A and B is 5.2 x 105 newtons. Charges A and B are 2.4 x 102 meters apart. If the charge on particle A is 7.2 x 108 coulombs, what is the charge of particle B? (k 7 9.0 x 109 newton meters?/coulomb)
8 0
3 years ago
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