3 years ago

I need help balancing chemical equations

1 answer:

Gwar [14]3 years ago

4 0

Hey! The best way I learned is if when I write it out put a space where a number should be

You might be interested in

Molodets [167]

The shape, the cell wall, chlorophyll, the components of the nucleus, cytoplasm

8 0

2 years ago

svetlana [45]

Answer: There are $40.41 \times 10^{23}$ molecules present in 6.71 moles of $NH_{3}$ .

Explanation:

Given: Moles of $NH_{3}$ = 6.71 mol

According to the mole concept, 1 mole of every substance contains $6.022 \times 10^{22}$ molecules.

Therefore, molecules present in 6.71 moles are calculated as follows.

$Molecules = moles \times 6.022 \times 10^{23}\\= 6.71 \times 6.022 \times 10^{23}\\= 40.41 \times 10^{23}$

Thus, we can conclude that there are $40.41 \times 10^{23}$ molecules present in 6.71 moles of $NH_{3}$ .

6 0

3 years ago

dem82 [27]

D bc people can feel how hot u are

4 0

3 years ago

Flura [38]

Answer:

2 one is the correct one

Explanation:

5 0

2 years ago

tino4ka555 [31]

Here are a few examples :)

iodine (I2)

naphthalene

aresenic (As)

ferrocene

water (H2O)

carbon dioxide (CO2)

Hope this helps :)

5 0

3 years ago