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cupoosta [38]
3 years ago
10

a milk carton filled with water is hanging from a string. what will happen if you punch two holes in opposite sides of the carto

n at the opposite corners?
Physics
1 answer:
marin [14]3 years ago
3 0
When you punch holes in opposite corners of a milk carton filled with water which is hanging from a string, water will start to flow outside with a certain force. There will be a reaction equal and opposite to this force that will make the milk carton start to spin.

This is a typical example of water turbine that is used to demonstrate the third Newton's law.
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What is the predicted result when two different materials of equal mass absorb the same amount of energy by heat flow?
Ludmilka [50]

The correct is D.

Explanation: The specific heat is defined as heat required to raise the temperature of a unit mass by one degree. Greater the specific heat, more is the heat required to raise the temperature for equal mass. So, the temperature of the material with lowest specific heat will increase the most for the same amount of heat energy.

7 0
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If bullets are fired from an airplane in the forward direction of its motion, the momentum of the airplane will be:_______
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luda_lava [24]

Answer:

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Explanation:

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2 years ago
If a small number of tree frogs migrate to a mat of vegetation that is already home to an established population of tree frogs a
Bingel [31]

Answer:

D

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5 0
3 years ago
On a hot summer day, 3.50 ✕ 106 J of heat transfer into a parked car takes place, increasing its temperature from 36.5°C to 44.4
anygoal [31]

Answer:

a) \Delta s=443037.9747\ J.K^{-1}

b) \Delta s=31868131.8681\ J.K^{-1}

Explanation:

a)

Given:

amount of heat transfer occurred,dQ=3.5\times 10^6\ J

initial temperature of car, T_i=36.5+273=309.5\ K

final temperature of car, T_f=44.4+273=317.4\ K

We know that the change in entropy is given by:

\Delta s=\frac{dQ}{T_f-T_i}

\Delta s=\frac{3.5\times 10^6}{(44.4-36.5)} (heat is transferred into the system of car)

\Delta s=443037.9747\ J.K^{-1}

b)

amount of heat transfer form the system of house, dQ=5.8\times 10^8\ J

initial temperature of house, T_i=23.5+273=296.5\ K

final temperature of house, T_f=5.3+273=278.3\ K

\Delta s=\frac{dQ}{T_f-T_i}

\Delta s=\frac{5.8\times 10^8}{278.3-296.5}

\Delta s=31868131.8681\ J.K^{-1}

6 0
3 years ago
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